How to create IN OUT or OUT parameters in Java

23,871

Solution 1

My question would be: Why doesn't method return something? Rather than setting an in/out argument?

But assuming you absolutely, positively must have an in/out argument, which is a whole different question, then the array trick is fine. Alternately, it's not less clumsy, but the other way is to pass in an object reference:

public class Foo {
    private String value;

    public Foo(String v) {
        this.value = v;
    }

    public String getValue() {
        return this.value;
    }

    public void setValue(String v) {
        this.value = v;
    }
 }

 // ....
 public void method(String in, Foo inOut) {
     inOut.setValue(in);
 }

(Or, of course, just make value public.) See? I said it wasn't less clumsy.

But I'd ask again: Can't method return something? And if it needs to return multiple things, can't it return an object instance with properties for those things?

Off-topic: This is one of the areas where I really like the C# approach. One of the arguments against in/out arguments is that they're unclear at the point where you're calling the function. So C# makes you make it clear, by specifying the keyword both at the declaration of the function and when calling it. In the absense of that kind of syntactic help, I'd avoid "simulating" in/out arguments.

Solution 2

Java copies anything you pass as an argument. If you pass a primitive, inside method you have copy of that primitive, and no modifications will affect the actual variable outside method. If you pass object, you pass copy of reference, which actually references to the original object. This is the way how you can propagate modifications to the context of something that called the method - by modifying the state of the object that the reference is 'pointing' to. See more on this: Does Java Pass by Value or by Reference?

Solution 3

There's no direct way. Other technique include:

  • Passing a holder object (a bit like your 1-ary array)
  • Using, e.g., an AtomicInteger
  • Passing a more useful object from a business perspective that happens to be mutable
  • A callback to a custom interface for receiving the result

If you think about it, the array trick is not dissimilar to passing a T* in C/C++

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Lukas Eder
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Lukas Eder

I am the founder and CEO at Data Geekery, the company behind jOOQ.

Updated on July 09, 2022

Comments

  • Lukas Eder
    Lukas Eder almost 2 years

    In PL/SQL (or many other languages), I can have IN OUT or OUT parameters, which are returned from a procedure. How can I achieve a similar thing in Java?

    I know this trick:

    public void method(String in, String[] inOut, String[] inOut2) {
      inOut[0] = in;
    }
    

    Where the in parameter represents an IN parameter and the inOut parameter can hold a return value. The convention would be that String[] inOut is an array of inOut.length == 1.

    That's kind of clumsy.

    EDIT Feedback to answers: Other tricks include:

    • holder/wrapper classes, but I don't want to introduce any new types, callbacks, etc.
    • return values: I'd like a general solution. I.e. one with several IN OUT parameters involved.
    • wrapper for IN OUT parameter as a return value: That's a viable option, but still not so nice, because that wrapper would have to be generated somehow

    Does anyone know a better way to achieve this generally? The reason I need a general solution is because I want to generate convenience source code from PL/SQL in a database schema.

  • Lukas Eder
    Lukas Eder over 13 years
    Thanks for your hints. I thought about those things as well, unfortunately, they won't work in my case...
  • Lukas Eder
    Lukas Eder over 13 years
    Thanks, I know that Java doesn't pass actual pointers but "reference copies". That's why I came up with the array trick. That's a very common way to simulate pointers in Java...
  • Platinum Azure
    Platinum Azure over 13 years
    +1 for actually explaining the pass-by-value semantics Java uses in a logical manner. There are too few people like you in today's world...
  • T.J. Crowder
    T.J. Crowder over 13 years
    @Lukas: I know that Java doesn't pass actual pointers but "reference copies" Which is just another term for pointers. ;-)
  • Lukas Eder
    Lukas Eder over 13 years
    The method won't be able to return a single value, because I need a general solution. I have adapted the example to hold several IN OUT parameters. But maybe returning a generated result object (holding the IN OUT parameters) might actually be an option. +1 for that.
  • Lukas Eder
    Lukas Eder over 13 years
    You're right about your off-topic comment. In general I don't need IN OUT parameters. But as I'm generating source code from actual PL/SQL code, I can't do without... :-/
  • Lukas Eder
    Lukas Eder over 13 years
    @T.J. Crowder: As far as I know in C/C++, you can assign a new value to a pointer that will be able to leave the scope of the method. In Java, this is not possible, as Arturs correctly explained. The "pointer" is passed by value to the method, not by reference
  • T.J. Crowder
    T.J. Crowder over 13 years
    @Lukas: "As far as I know in C/C++, you can assign a new value to a pointer that will be able to leave the scope of the method. In Java, this is not possible..." Java's object references (void foo(MyObject m)) are exact analogs of C/C++ pointers (void foo(MyObject *pm)). You can assign to m (Java), or mp (C/C++), but that doesn't have any effect on anything outside foo. But C/C++ has pointers to pointers: void foo(MyObject **ppm), where the effect of writing to *ppm can be seen in the calling method. Java's analog is the array trick the OP flagged up.
  • T.J. Crowder
    T.J. Crowder over 13 years
    @Lukas: (continuing) But granted, I'm not immediately thinking of a Java equivalent to a pointer to a pointer to a pointer, void foo(MyObject ***pppm). :-)
  • Lukas Eder
    Lukas Eder over 13 years
    OK, that's what I meant. Thanks for the clarification
  • André Fratelli
    André Fratelli almost 8 years
    In my case I need inout because the method is already returning something else.
  • Marcin K.
    Marcin K. over 2 years
    @T.J.Crowder Oh right I'm sorry. I should have read more carefully.