How to divide 2 int in c?

Question

wanna divide 2 numbers and get the result like this:

5 / 2 = 2.50

But it only outputs 2.

I don't now what i'm doing wrong.

Here my code:

int a;
int b;
int c;
printf("First num\n");
scanf("%d", &a);
printf("Second num\n");
scanf("%d", &b);
c = a / b;
printf("%d", c);

Solution 1

You need a double variable to store the result. int stores only integers. Additionally, you have to typecast the other variables also before performing the division.

---

Do something like this

double c;
.
.
.
c = (double)a / (double)b;
printf("%f", c);

---

NOTE:

You do not need the & in printf() statements.

Solution 2

To avoid the typecast in float you can directly use scanf with %f flag.

float a;
float b;
float c;
printf("First number\n");
scanf("%f", &a);
printf("Second number\n");
scanf("%f", &b);
c = a / b;
printf("%f", c);

Solution 3

The '/' - sign is for division. Whenever in C language, you divide an integer with an integer and store the data in an integer, the answer as output is an integer. For example

int a = 3, b = 2, c = 0;
c = a/b; // That is c = 3/2;
printf("%d", c);

The output received is: 1
The reason is the type of variable you have used, i.e. integer (int)
Whenever an integer is used for storing the output, the result will be stored as integer and not a decimal value.

For storing the decimal results, C language provide float, double, long float and long double.

Whenever you perform an operation and desires an output in decimal, then you can use the above mentioned datatypes for your resultant storage variable. For example

int a = 3, b = 2;
float c = 0.0;
c = (float)a/b; // That is c = 3/2;
printf("%.1f", c);

The output received: 1.5
So, I think this will help you to understand the concept.
Remember: When you are using float then the access specifier is %f. You need to convert your answer into float, just as I did, and then the answer will be reflected.

Solution 4

You have to use float or double variables, not int (integer) ones. Also note that a division between two integers will lead to an integer result, meanwhile a division between a float/double and an integer will lead to a float result. That's because C implicitly promote this integer to float.

For example:

5/2 = 2
5/2.0f = 2.5f

Note the .0f, this actually means that we are dividing with a float.

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Comments

[Jaffer Wilson]

@user3528438 You think that I have copied the answer from there? Let me tell you that it was my own sample. I have just got some figures to support my answer. And I don't know why you have devoted me, I haven't wrote anything wrong. My answer is appropriate.

[user3528438]

No, I copied your code to there to show why I downvoted: your answer is not correct (take a look at the stdout, or try to compile and run your code yourself).

[Jaffer Wilson]

@user3528438 Yes you were correct. Now I have edited my answer. Please check it. I hope this will satisfy you.. ok. and thank you for showing me that I was wrong. Here I have tested it too: ideone.com/ibwTpu

[Yunnosch]

"only an int type number is displayed", what is displayed is clearly a floating point value. "5/2 gives a floating point type number", no it does not, that is the core of the problem.

[Bob]

I think user9598609 understands what is going on. The answer was just worded poorly. A little more detail in the answer would have been helpful. 5/2 DOES yield a floating point value; unfortunately, in C, it takes a bit more work to reveal it.