How to divide float by integer when both are variables?

Question

I am writing a program in C. I have two variables one of which is integer and the other one is float. I want to divide the float by the integer and want to get result in float. I am doing the following:

int a;
float b=0,c=0;
scanf("%d",&a);

I then do some computations on b so it has a non-zero value.

c = b/(float)a;
printf("c = %d\n", c);

The problem is I am getting c printed as a rounded number (integer) rather than a float value.

How can I get c as a float value?

Solution 1

Your problem is here:

printf("c = %d\n", c);

%d formats c as integer. Use %f instead.

Or std::cout << "c = " << c << std::endl if you prefer.

Solution 2

For those here coming from a Google search because of the question's name:

The result of dividing a float by an integer is a float, this is clean and safe. Example:

#include <iostream>

int main()
{
    float y = 5.0f;
    int x = 4;
    std::cout << y/x << std::endl;
}

The output is as expected: 1.25

Solution 3

When printing on a screen try this (this worked for me):

printf("c = %f\n", c);