How to embed bash script directly inside a git alias

Question

Can I embed the following bash shell code:

for name in $(git diff --name-only $1); do git difftool $1 $name & done

directly into the creation of a git alias:

git config --global alias.diffall ***my-bash-code-here***

This leads on from my previous question/answer on SO, where I put the code into a .sh file and then aliased to the file:

git config --global alias.diffall '!sh diffall.sh'

But in the never-ending quest for simplicity, there's gotta be a way to skip the file and insert code directly into the alias? I can't figure out the format...

Solution 1

git config --global alias.diffall '!sh diffall.sh'

This is redundant in one way. If you are going to add 'diffall.sh' into your $PATH anyway, why not save it as 'git-diffall', and save yourself from declaring an alias. Yes, "git diffall" will run it.

Solution 2

To run commands inside of a git alias, and in particular to pass arguments to those commands, you will likely have to create a temporary function which you then immediately invoke:

$ vim ~/.gitconfig
...
[alias]
    # compare:
    foo = "! echo begin arg=$1/$2/end"
    foo2 = "!f() { echo "begin arg=$1/$2/end"; }; f"

In this example, the function is probably what you need (and is also more flexible as to what you can do in a single "statement"); and you can probably tell that for both options, the remaining args to the git command are simply passed as args to the alias, regardless if it's "echo" or "f"; invoking the function simply consumes the args, ignoring what's not explicitly used:

$ git foo a b c
begin arg=a/b/end a b c

$ git foo2 a b c
begin arg=a/b/end

Another example (lists all aliases, based on matching pattern) (note: you can keep reusing the same function name "f()" throughout the .gitconfig):

[alias]
    alias = "!f() { git config --get-regexp "^alias.${1}$" ; }; f"

The first returns the alias for just "foo$", the second for "foo.*":

$ git alias foo
alias.foo ! echo begin arg=$1/$2/end

$ git alias 'foo.*'
alias.foo ! echo begin arg=$1/$2/end
alias.foo2 !f() { echo begin arg=$1/$2/end; }; f

(nb: actual results may vary based on shell; I'm using this with bash on Linux, Unix & Cygwin (Windows).)

Solution 3

I couldn't find in documentation, but if you create a script "git-<name>" in path, you can call it with "git name" in your repo.

See:

$ cd ~/bin
$ echo "echo I love this log:
>pwd
>git log --graph  --summary --decorate --all" > git-logg
$ chmod +x git-logg
$ cd /path/to/your/repo
$ git logg
I love this log:
/path/to/your/repo
* commit 3c94be44e4119228cc681fc7e11e553c4e77ad04 (whatever-branch)
| Author: myself <my@Laptop.(none)>
| Date:   Fri Apr 1 16:47:20 2011 +0200
| 
|     would have been better not to do it at all
| 
...
$

So, you can write any alias you like with this (rather obscure) way too.

Even more you can add autocompletion to that new command defining a function. Info here

$ _git_logg ()
{
  # you can return anything here for the autocompletion for example all the branches
  __gitcomp_nl "$(__git_refs)" 
}

Solution 4

Adding these 2 line to your .git/config file should do the trick.

[alias]
    diffall = '!for name in $(git diff --name-only $1); do git difftool $1 $name & done'

Edit: presumably the git-config version works too, but I like to keep my aliases in the config file for ease of management.

There is a nice page on the git wiki that explains aliases very clearly: http://git.or.cz/gitwiki/Aliases In particular, read 'advanced aliases with arguments'

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