How to find a whole word in a String in Java?

Question

I have a String that I have to parse for different keywords. For example, I have the String:

"I will come and meet you at the 123woods"

And my keywords are

'123woods'
'woods'

I should report whenever I have a match and where. Multiple occurrences should also be accounted for.

However, for this one, I should get a match only on '123woods', not on 'woods'. This eliminates using String.contains() method. Also, I should be able to have a list/set of keywords and check at the same time for their occurrence. In this example, if I have '123woods' and 'come', I should get two occurrences. Method execution should be somewhat fast on large texts.

My idea is to use StringTokenizer but I am unsure if it will perform well. Any suggestions?

Solution 1

The example below is based on your comments. It uses a List of keywords, which will be searched in a given String using word boundaries. It uses StringUtils from Apache Commons Lang to build the regular expression and print the matched groups.

String text = "I will come and meet you at the woods 123woods and all the woods";

List<String> tokens = new ArrayList<String>();
tokens.add("123woods");
tokens.add("woods");

String patternString = "\\b(" + StringUtils.join(tokens, "|") + ")\\b";
Pattern pattern = Pattern.compile(patternString);
Matcher matcher = pattern.matcher(text);

while (matcher.find()) {
    System.out.println(matcher.group(1));
}

If you are looking for more performance, you could have a look at StringSearch: high-performance pattern matching algorithms in Java.

Solution 2

Use regex + word boundaries as others answered.

"I will come and meet you at the 123woods".matches(".*\\b123woods\\b.*");

will be true.

"I will come and meet you at the 123woods".matches(".*\\bwoods\\b.*");

will be false.

Solution 3

Hope this works for you:

String string = "I will come and meet you at the 123woods";
String keyword = "123woods";

Boolean found = Arrays.asList(string.split(" ")).contains(keyword);
if(found){
      System.out.println("Keyword matched the string");
}

http://codigounico.blogspot.com/

Solution 4

How about something like Arrays.asList(String.split(" ")).contains("xx")?

See String.split() and How can I test if an array contains a certain value.

Solution 5

public class FindTextInLine {
    String match = "123woods";
    String text = "I will come and meet you at the 123woods";

    public void findText () {
        if (text.contains(match)) {
            System.out.println("Keyword matched the string" );
        }
    }
}

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