How to get data on database and display in "select" dropdown in view (Codeigniter)

Question

I am a newbie to CodeIgniter, I have created a simple app that will fetch data from database and then display it in a <SELECT> dropdown. I'm trying to get data from a specific field from database to my view. So far, I have tried the code below (not working):

My model (datamodel.php),

function getbanklist() {
    $banklist = array();
    $this->db->select("id, bank");
    $this->db->from('bank');
    $query = $this->db->get();

    if ($query->num_rows >= 1){
        foreach($query->result_array() as $row){
            $banklist[$row['id']]=$row['bank'];
        }
        return $banklist;
    }
}

My controller (home.php),

function index(){
    $data['bankdata'] = $this->datamodel->getbanklist();
    $this->load->view('viewdata', $data);
}

My view (viewdata.php),

<tr>
    <th>BANK</th>
    <td>
        <div class="containers">
            <select name="bank">
            <?php foreach($bankdata as $bank){
                echo '<option value="'.$bank['id'].'">'.$bank['bank'].'</option>';
            } ?>
            </select>
        </div>
    </td>
</tr>

My database structure (see here),

id    bank
------------
0     Bank 1
1     Bank 2
2     Bank 3
3     Bank 4
4     Bank 5

Solution

Try this:

Model:

function getbanklist() {
    $this->db->select("id,bank");
    $this->db->from('bank');
    $query = $this->db->get();
    return $query;
}

In your view:

<select name="bank">
<?php foreach($bankdata->result() as $bank){ ?>
    <option value="<?php echo $bank->id ?>"><?php echo $bank->bank ?></option>
<?php } ?>
</select>

Comments

[Brian Luna]

I got error, it shows error : Call to a member function result() on a non-object in

[Kavin Smk]

did you change your model??

[Brian Luna]

yes. I did. maybe I'm messing up with my code. I'll check all. thanks

[Brian Luna]

it works. I messed up with my old code. thanks @KavinSmk

[raja]

It is not loading dropdown list in view page.