How to get jqGrid current search criteria?

Question

I need to get the exact same thing the jqGrid passes on the GET/POST _search parameter.

How can I do this?

Solution 1

Just to close this question I did this this the following line:

grid.getGridParam("postData").filters;

With this I get the filter expression the jqGrid generates when we're applying filters on its data.

Solution 2

$('#myGrid').getGridParam("postData").filters;

will give you a string (i don't know why string. why not JSON)

"{"groupOp":"AND","rules":[{"field":"Name","op":"bw","data":"a"}]}" 

rules have the search criteria. If i have multiple search criteria, all would be there

"{"groupOp":"AND","rules":[{"field":"Name","op":"bw","data":"a"},{"field":"Description","op":"bw","data":"d"}]}" 

Solution 3

var search = grid.getGridParam("postData").search;

...works for me.

Comments

[AlexCode]

Thanks! My question body isn't quite correct, what I want isn't the _search which is a boolean but the filters that actually contains the json representation of the current filter applyed on the grid. So the way of getting is: grid.getGridParam("postData").filters;

[Kevin Gauthier]

I don't understand what it is that you're asking for.

[bkwdesign]

The new API mode will look like this: $('#myGrid').jqGrid('getGridParam', "postData").filters

[low_rents]

I also don't understand why it returns a string and not JSON.

[Sergiy Ostrovsky]

This doesn't work for me when using datatype: "json".