How to get string from ASCII code in Swift?

Question

How can I get a character from a ASCII code in Apple's new Swift?

For example 65 would returns "A".

Solution

As a character:

let c = Character(UnicodeScalar(65))

Or as a string:

let s = String(UnicodeScalar(UInt8(65)))

Or another way as a string:

let s = "\u{41}"

(Note that the \u escape sequence is in hexadecimal, not decimal)

Comments

[Klaas]

If you know the code at compile time you just can use: println("The Character A: \u{41}") to print arbitrary unicode scalars. See developer.apple.com/library/ios/documentation/Swift/Conceptu‌​al/… and en.wikipedia.org/wiki/Basic_Latin_(Unicode_block)

[YourMJK]

Exactly what I needed. Thanks!

[Martin R]

@M.J.K: See stackoverflow.com/questions/24102044/….

[Martin R]

@nikoss: Updated so that it works with Swift 2 and 3. Thanks for letting me know!