How to get sum of an array object keys in underscore.js?
11,305
Solution 1
Not very pretty, but I think the fastest method is to do it like this
_(items).reduce(function(acc, obj) {
_(obj).each(function(value, key) { acc[key] = (acc[key] ? acc[key] : 0) + value });
return acc;
}, {});
Or, to go really over the top (I think it will can be faster than above one, if you use lazy.js instead of underscore):
_(items).chain()
.map(function(it) { return _(it).pairs() })
.flatten(true)
.groupBy("0") // groups by the first index of the nested arrays
.map(function(v, k) {
return [k, _(v).reduce(function(acc, v) { return acc + v[1] }, 0)]
})
.object()
.value()
Solution 2
For aggregating I'd recommend reduce
:
_.reduce(items, function(acc, o) {
for (var p in acc) acc[p] += o[p] || 0;
return acc;
}, {price1:0, price2:0, price3:0});
Or better
_.reduce(items, function(acc, o) {
for (var p in o)
acc[p] = (p in acc ? acc[p] : 0) + o[p];
return acc;
}, {});
Author by
Erik
Updated on June 08, 2022Comments
-
Erik almost 2 years
I have the following array:
var items = [ {price1: 100, price2: 200, price3: 150}, {price1: 10, price2: 50}, {price1: 20, price2: 20, price3: 13}, ]
I need to get object with sum of all keys like the following:
var result = {price1: 130, price2: 270, price3: 163};
I know I may to use just loop but I'm looking for a approach in underscore style :)