How to get sum of an array object keys in underscore.js?

11,305

Solution 1

Not very pretty, but I think the fastest method is to do it like this

_(items).reduce(function(acc, obj) {
  _(obj).each(function(value, key) { acc[key] = (acc[key] ? acc[key] : 0) + value });
  return acc;
}, {});

Or, to go really over the top (I think it will can be faster than above one, if you use lazy.js instead of underscore):

_(items).chain()
  .map(function(it) { return _(it).pairs() })
  .flatten(true)
  .groupBy("0") // groups by the first index of the nested arrays
  .map(function(v, k) { 
    return [k, _(v).reduce(function(acc, v) { return acc + v[1] }, 0)]     
  })
  .object()
  .value()

Solution 2

For aggregating I'd recommend reduce:

_.reduce(items, function(acc, o) {
    for (var p in acc) acc[p] += o[p] || 0;
    return acc;
}, {price1:0, price2:0, price3:0});

Or better

_.reduce(items, function(acc, o) {
    for (var p in o)
        acc[p] = (p in acc ? acc[p] : 0) + o[p];
    return acc;
}, {});
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11,305
Erik
Author by

Erik

Updated on June 08, 2022

Comments

  • Erik
    Erik almost 2 years

    I have the following array:

    var items = [
       {price1: 100, price2: 200, price3: 150},
       {price1: 10, price2: 50},
       {price1: 20, price2: 20, price3: 13},
    ]
    

    I need to get object with sum of all keys like the following:

    var result = {price1: 130, price2: 270, price3: 163};
    

    I know I may to use just loop but I'm looking for a approach in underscore style :)