How to get tag name of root element in an XML document w/ XSLT?
Solution 1
I think you want to retrieve the name of the outermost XML element. This can be done like in the following XSL sample:
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:variable name="outermostElementName" select="name(/*)" />
<xsl:template match="/">
<xsl:value-of select="$outermostElementName"/>
</xsl:template>
</xsl:stylesheet>
Please note that there is a slight difference in XPath terminology:
The top of the tree is a root node (1.0 terminology) or document node (2.0). This is what "/" refers to. It's not an element: it's the parent of the outermost element (and any comments and processing instructions that precede or follow the outermost element). The root node has no name.
See http://www.dpawson.co.uk/xsl/sect2/root.html#d9799e301
Solution 2
Use the XPath name()
function.
One XPath expression to obtain the name of the top (not root!) element is:
name(/*)
The name() function returns the fully-qualified name of the node, so for an element <bar:foo/>
the string "bar:foo" will be returned.
In case only the local part of the name is wanted (no prefix and ":"), then the XPath local-name()
function should be used.
Solution 3
Figured it out. The function name() given the parameter * will return foo.
Brian
Just a guy, getting by, with a little help from my stackoverflow friends.
Updated on December 16, 2020Comments
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Brian over 3 years
I'm interested in assigning the tag name of the root element in an xml document to an xslt variable. For instance, if the document looked like (minus the DTD):
<foo xmlns="http://....."> <bar>1</bar> </foo>
and I wanted to assign the string 'foo' to an xslt variable. Is there a way to reference that?
Thanks, Matt
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Dimitre Novatchev over 15 years@annakata: name() and local-name() are differnt. The OP clearly wants name(). Nowhere does he say that he wants the name stripped off any namespace prefix.
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Diego Queiroz over 5 yearsAlternatively
/*/name()
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Dimitre Novatchev over 5 years@DiegoQueiroz,
/*/name()
will raise an error if one uses an XPath 1 processor, while name(/*) works nicely both with XPath 1.0 processors and with ones that implement versions higher than 1.0. So, 100% of the readers of this answer will benefit from it, while probably 80% will be frustrated by the failure to use/*/name()
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Diego Queiroz over 5 yearsGood point, but sometimes you're not after compatibility. I was using a processor that forces me to specify a base XPath to loop (eg. /*), and then map the remaining XPath to fields. This way, my proposed solution was handy. But it is good to know it isn't compatible with older versions.