How to get URL parameter using jQuery or plain JavaScript?
Solution 1
Best solution here.
var getUrlParameter = function getUrlParameter(sParam) {
var sPageURL = window.location.search.substring(1),
sURLVariables = sPageURL.split('&'),
sParameterName,
i;
for (i = 0; i < sURLVariables.length; i++) {
sParameterName = sURLVariables[i].split('=');
if (sParameterName[0] === sParam) {
return sParameterName[1] === undefined ? true : decodeURIComponent(sParameterName[1]);
}
}
return false;
};
And this is how you can use this function assuming the URL is,
http://dummy.com/?technology=jquery&blog=jquerybyexample
.
var tech = getUrlParameter('technology');
var blog = getUrlParameter('blog');
Solution 2
Solution from 2021
We have: http://example.com?sent=yes
let searchParams = new URLSearchParams(window.location.search)
Does sent exist?
searchParams.has('sent') // true
Is it equal to "yes"?
let param = searchParams.get('sent')
and then just compare it.
Solution 3
jQuery code snippet to get the dynamic variables stored in the url as parameters and store them as JavaScript variables ready for use with your scripts:
$.urlParam = function(name){
var results = new RegExp('[\?&]' + name + '=([^&#]*)').exec(window.location.href);
if (results==null) {
return null;
}
return decodeURI(results[1]) || 0;
}
example.com?param1=name¶m2=&id=6
$.urlParam('param1'); // name
$.urlParam('id'); // 6
$.urlParam('param2'); // null
example params with spaces
http://www.jquery4u.com?city=Gold Coast
console.log($.urlParam('city'));
//output: Gold%20Coast
console.log(decodeURIComponent($.urlParam('city')));
//output: Gold Coast
Solution 4
I always stick this as one line. Now params has the vars:
params={};location.search.replace(/[?&]+([^=&]+)=([^&]*)/gi,function(s,k,v){params[k]=v})
multi-lined:
var params={};
window.location.search
.replace(/[?&]+([^=&]+)=([^&]*)/gi, function(str,key,value) {
params[key] = value;
}
);
as a function
function getSearchParams(k){
var p={};
location.search.replace(/[?&]+([^=&]+)=([^&]*)/gi,function(s,k,v){p[k]=v})
return k?p[k]:p;
}
which you could use as:
getSearchParams() //returns {key1:val1, key2:val2}
or
getSearchParams("key1") //returns val1
Solution 5
Yet another alternative function...
function param(name) {
return (location.search.split(name + '=')[1] || '').split('&')[0];
}
LeBlaireau
Updated on July 30, 2022Comments
-
LeBlaireau almost 2 years
I have seen lots of jQuery examples where parameter size and name are unknown.
My URL is only going to ever have 1 string:
http://example.com?sent=yes
I just want to detect:
- Does
sent
exist? - Is it equal to "yes"?
- Does