How to get value returned from async Task<string> function(); in C#

Question

I have an async method and I want to get a message from the same method when it gets done.

Below is the code

 static async Task<string> pizza()
        {
            await Task.Delay(10);
            for (int i = 0; i < 100; i++)
            {
                //Console.WriteLine("Processing pizza...");
            }
            return "Pizza is ready";

        } 

And I want to get receive this message at calling point

....... code 
Task t=null;
            switch (option)
            {
                case 1:
                    {

                        await Task.Run(() =>
                        {

                         t=pizza();// asynchronous method  

                        });
                        Console.WriteLine(t.ToString());
                    }
                    break;
 .... other code

Solution 1

Do you need the Task.Run part? You can await of you are inside an async method:

var result = await pizza();

Console.WriteLine(result);

You can also call result:

var result = pizza().Result;

Solution 2

You can either

var pizza = await pizza();

Or

var pizza = pizza().GetAwaiter().GetResult();