How to handle launch options in Swift 3 when a notification is tapped? Getting syntax problems

Question

I am trying to handle the launch option and open a specific view controller upon tapping a remote notification that I receive in swift 3. I have seen similar question, for instance here, but nothing for the new swift 3 implementation. I saw a similar question (and ) In AppDelegate.swift I have the following in didFinishLaunchingWithOptions:

    var localNotif = (launchOptions[UIApplicationLaunchOptionsRemoteNotificationKey] as! String)
if localNotif {
    var itemName = (localNotif.userInfo!["aps"] as! String)
    print("Custom: \(itemName)")
}
else {
    print("//////////////////////////")
}

but Xcode is giving me this error:

Type '[NSObject: AnyObject]?' has no subscript members

I also tried this:

   if let launchOptions = launchOptions {
        var notificationPayload: NSDictionary = launchOptions[UIApplicationLaunchOptionsRemoteNotificationKey] as NSDictionary!

    }

and I get this error:

error: ambiguous reference to member 'subscript'

I got similar errors wherever I had previously used similar code to get a value from a dictionary by the key and I had to replace the codes and basically safely unwrap the dictionary first. But that doesn't seem to work here. Any help would be appreciated. Thanks.

Solution 1

So it turned out the whole method signature has changed and when I implemented the new signature things worked just fine. Below is the code.

new didFinishLaunchingWithOptions method:

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey : Any]? = nil) -> Bool {



//and then 
 if launchOptions?[UIApplicationLaunchOptionsKey.remoteNotification] != nil {


// Do what you want to happen when a remote notification is tapped.


}

}

Hope this helps.

Solution 2

Apple made plenty of changes in Swift 3 and this one of them.

Edit: This works for Swift 4 as well.

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
    //Launched from push notification
    let remoteNotif = launchOptions?[UIApplicationLaunchOptionsKey.remoteNotification] as? [String: Any]
    if remoteNotif != nil {
        let aps = remoteNotif!["aps"] as? [String:AnyObject]
        NSLog("\n Custom: \(String(describing: aps))")
    }
    else {
        NSLog("//////////////////////////Normal launch")
    }
}

Swift 5:

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplication.LaunchOptionsKey: Any]?) -> Bool {
    //Launched from push notification
    guard let options = launchOptions,
        let remoteNotif = options[UIApplication.LaunchOptionsKey.remoteNotification] as? [String: Any]
        else {
            return
    }
    let aps = remoteNotif["aps"] as? [String: Any]
    NSLog("\n Custom: \(String(describing: aps))")
    
    handleRemoteNotification(remoteNotif)
}

And for more on LaunchOptionsKey read Apple's documentation.

Solution 3

Swift 4

// Check if launched from the remote notification and application is close
 if let remoteNotification = launchOptions?[.remoteNotification] as?  [AnyHashable : Any] {
            // Do what you want to happen when a remote notification is tapped.
            let aps = remoteNotification["aps" as String] as? [String:AnyObject]
            let apsString =  String(describing: aps)
            debugPrint("\n last incoming aps: \(apsString)")
    }