How to keep variable constant even after page refresh in PHP
31,193
You could use a hidden input:
<form method="POST">
<input type="text" />
<input type="hidden" name="word" value="<?php echo $word; ?>" />
</form>
...and on the next page:
if(isset($_POST['word'])) {
echo $_POST['word'];
}
Or you could use a PHP $_COOKIE, which can be called forever (but kind of a waste if you just want it on the next page):
setcookie('word', $word, time()+3600, '/');
...and on the next page:
echo $_COOKIE['word'];
Author by
Admin
Updated on July 09, 2022Comments
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Admin almost 2 years
I'm making a simple hangman application and I have my php file and a separate .txt file holding the words, one on each line.
What I want is for the $word variable to remain constant even after the page refreshes since I was planning on using a GET or POST to get the user's input.
In the example code below I want $word to stay the same after the form is submitted. I believe it's a simple matter of moving code to another place but I can't figure out where any help for this PHP noob would be appreciated!
wordsEn1.txt:
cat dog
functions.php:
<?php function choose_word($words) { return trim($words[array_rand($words)]); } ?>
hangman.php:
<?php include('functions.php'); $handle = fopen('wordsEn1.txt', 'r'); $words = array(); while(!feof($handle)) { $words[] = trim(fgets($handle)); } $word = choose_word($words); echo($word); echo('<form><input type="text" name="guess"></form>'); ?>
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Admin about 8 yearsThis will not work if the user presses F5 to refresh.