How to list files in a zip without extra information in command line
93,297
zipinfo -1 file.zip
Or:
unzip -Z1 file.zip
Would list only the files.
If you still want the extra info for each file names, you could do:
unzip -Zl file.zip | sed '1,2d;$d'
Or:
unzip -l file.zip | sed '1,3d;$d' | sed '$d'
Or (assuming GNU head
):
unzip -l file.zip | tail -n +4 | head -n -2
Or you could use libarchive
's bsdtar
:
$ bsdtar tf test.zip
file1.txt
file2.txt
file3.txt
$ bsdtar tvf test.zip
-rw-rw-r-- 0 1000 1000 810000 Jul 5 2014 file1.txt
-rw-rw-r-- 0 1000 1000 810000 Jul 5 2014 file2.txt
-rw-rw-r-- 0 1000 1000 810000 Jul 5 2014 file3.txt
$ bsdtar tvvf test.zip
-rw-rw-r-- 0 1000 1000 810000 Jul 5 2014 file1.txt
-rw-rw-r-- 0 1000 1000 810000 Jul 5 2014 file2.txt
-rw-rw-r-- 0 1000 1000 810000 Jul 5 2014 file3.txt
Archive Format: ZIP 2.0 (deflation), Compression: none
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Author by
Mike
Updated on September 18, 2022Comments
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Mike over 1 year
In my bash command line, when I use
unzip -l test.zip
I get the output like this:Archive: test.zip Length Date Time Name --------- ---------- ----- ---- 810000 05-07-2014 15:09 file1.txt 810000 05-07-2014 15:09 file2.txt 810000 05-07-2014 15:09 file3.txt --------- ------- 2430000 3 files
But I am interested only by the lines containing the file details.
I tried to make filtering using grep like this:
unzip -l test.zip | grep -v Length | grep -v "\-\-\-\-" | g -v Archive | grep -v " files"
But it is long and prone to error (e.g a file name Archive in this list will be dropped)
Is there any other options with unzip -l (I checked the unzip man page and did not find any) or another tool to do so?
It is important to me to not really unzip the archive but just to look what files are inside.
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tripleee over 6 yearsThe accepted answer is much better than this; but I want to remark that anything with multiple
grep
can be refactored into an Awk script, usually with much improved precision.awk 'NR >3 { if (/^ *---/) exit 0; print }'
would trim the first three lines as well as the footer, and also be within reach of easily extracting just the file name (hint:print substr($0, 29)
). -
Mike over 6 yearsYes, I totally agree, that's is exactly why I ask that specific question: to have a better and viable solution.
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Mike about 10 yearsthanks powerful sed... exactly what I wanted; Also the zipinfo tool is interesting, I didn't know it.
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Matt over 4 yearsIs there a way to ignore directories?
unzip -Z1 zipfile.zip
will output: directory/ and directory/file.extension (Note: directory names with . is likely, so adding a| grep .
doesn't work) -
michael almost 4 yearsI was also looking for a way to exclude directories from the listing (
bsdtar -tf
also prints directories just likeunzip -Z1
), afaik this may be the only option:unzip -Z1 test.zip | grep -v '/$'
, since all entries that are just directory names have a trailing slash (/
). nb: however, if the goal was to remove directory prefix from the path, then each line would have to be processed withbasename
or bash equivalent stackoverflow.com/questions/965053/…