How to make action on node.js server after button click using jQuery AJAX
35,394
Solution 1
Your problem is here, you have forgotten the #
for targeting element by id, so click would never be invoke.
$('#like').click(function(){
$.post('/test');
});
Solution 2
It looks like you aren't selecting the input tag correctly. If you want to select a DOM element by ID, you'll want to use '#IDname' as your selector.
For this example, that means changing it to
...
$('#like').click(function(){
...
This also might not fix the error entirely: using a an input field with a type of "submit", you will likely have to do something like this:
...
$('#like').click(function(e){
e.preventDefault();
...
to keep the default submit event on the input from "bubbling up."
Author by
kuba12
Updated on May 25, 2020Comments
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kuba12 almost 4 years
I have a problem. I want to make server do something after clicking on button. This is my HTML code:
<input name="like" id="like" value="Like" type="submit" /> <script> $('like').click(function(){ $.post('/test') }); </script>
and this is my server-side code:
app.post('/test', function (req, res) { console.log('works'); });
And it doesn't work.
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Mritunjay almost 10 yearsit should be saying something ?
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morkro almost 10 yearsWell, what do you expect?
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prava almost 10 yearscan it be
$('#like').click(function(){
instead of$('like').click(function(){
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kuba12 almost 10 yearsThanks prava I missed # :D
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