How to parse a byte string in Python 3?
12,573
I would recomend trying something like this...
arr = b'\xe0\xa6\xb8\xe0\xa6\x96 - \xe0\xa6\xb6\xe0\xa6\x96\n'
splt = arr.decode().split(' - ')
b_arr1 = splt[0].encode()
b_arr2 = splt[1].encode()
I tried it out in the python 3 terminal and it works fine.
Author by
srdg
Updated on June 07, 2022Comments
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srdg about 2 years
Basically, I have two bytestrings in a single line like this:
b'\xe0\xa6\xb8\xe0\xa6\x96 - \xe0\xa6\xb6\xe0\xa6\x96\n'
This is a unicode string that I'm importing from an online file using
urllib
, and I want to compare the individual bytestrings so that I can replace the wrong ones. However, I can't find out any way to parse the string so that I get\xe0\xa6\xb8\xe0\xa6\x96
and\xe0\xa6\xb6\xe0\xa6\x96
in two different variables.I tried converting it into a raw string like
str(b'\xe0\xa6\xb8\xe0\xa6\x96')
and the indexing actually works, but in that case I can't revert back to the original bytestring in the first place.Is it possible? Any help would be great!