How to parse a JSON string into JsonNode in Jackson?
Solution 1
A slight variation on Richards answer but readTree
can take a string so you can simplify it to:
ObjectMapper mapper = new ObjectMapper();
JsonNode actualObj = mapper.readTree("{\"k1\":\"v1\"}");
Solution 2
You need to use an ObjectMapper
:
ObjectMapper mapper = new ObjectMapper();
JsonFactory factory = mapper.getJsonFactory(); // since 2.1 use mapper.getFactory() instead
JsonParser jp = factory.createJsonParser("{\"k1\":\"v1\"}");
JsonNode actualObj = mapper.readTree(jp);
Further documentation about creating parsers can be found here.
Solution 3
A third variant:
ObjectMapper mapper = new ObjectMapper();
JsonNode actualObj = mapper.readValue("{\"k1\":\"v1\"}", JsonNode.class);
Solution 4
Richard's answer is correct. Alternatively you can also create a MappingJsonFactory
(in org.codehaus.jackson.map
) which knows where to find ObjectMapper
. The error you got was because the regular JsonFactory
(from core
package) has no dependency to ObjectMapper
(which is in the mapper
package).
But usually you just use ObjectMapper
and do not worry about JsonParser
or other low level components -- they will just be needed if you want to data-bind parts of stream, or do low-level handling.
Solution 5
import com.github.fge.jackson.JsonLoader;
JsonLoader.fromString("{\"k1\":\"v1\"}")
== JsonNode = {"k1":"v1"}
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fadmaa
Updated on January 02, 2021Comments
-
fadmaa over 3 years
It should be so simple, but I just cannot find it after being trying for an hour.
I need to get a JSON string, for example,
{"k1":v1,"k2":v2}
, parsed as aJsonNode
.JsonFactory factory = new JsonFactory(); JsonParser jp = factory.createJsonParser("{\"k1\":\"v1\"}"); JsonNode actualObj = jp.readValueAsTree();
gives
java.lang.IllegalStateException: No ObjectCodec defined for the parser, can not deserialize JSON into JsonNode tree
-
jameshfisher over 9 years
#embarrasing
-- nope. If simple things aren't simple, then the API designer has failed, not you. -
Juan Rojas@StaxMan's answer in code: JsonFactory factory = new MappingJsonFactory();
-
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Matthew Herbst about 9 yearsFor anyone who needs an
ObjectNode
rather than aJsonNode
usemapper.valueToTree("{\"k1\":\"v1\"}")
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minexew about 8 years@MatthewHerbst In 2.5.1, this creates a new text node with the string "{\"k1\":\"v1\"}" rather than parsing it as JSON.