How to pass a variable by name to a Thread in Python?
49,885
Solution 1
Use the kwargs parameter:
threading.Thread(target=self._thread_function, args=(arg1,),
kwargs={'arg2':arg2}, name='thread_function').start()
Solution 2
you can also use lambda to pass args
threading.Thread(target=lambda: self._thread_function(arg1, arg2=arg2, arg3=arg3)).start()
Author by
Dylan
Updated on August 24, 2021Comments
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Dylan over 2 years
Say that I have a function that looks like:
def _thread_function(arg1, arg2=None, arg3=None): #Random code
Now I want to create a thread using that function, and giving it arg2 but not arg3. I'm trying to this as below:
#Note: in this code block I have already set a variable called arg1 and a variable called arg2 threading.Thread(target=self._thread_function, args=(arg1, arg2=arg2), name="thread_function").start()
The above code gives me a syntax error. How do I fix it so that I can pass an argument to the thread as arg2?