How to pass allocatable arrays to subroutines in Fortran
Solution 1
If a procedure has a dummy argument that is an allocatable, then an explicit interface is required in any calling scope.
(There are numerous things that require an explicit interface, an allocatable dummy is but one.)
You can provide that explicit interface yourself by putting an interface block for your subroutine inside the main program. An alternative and far, far, far better option is to put the subroutine inside a module and then USE that module in the main program - the explicit interface is then automatically created. There is an example of this on the eng-tips site that you provided a link to - see the post by xwb.
Note that it only makes sense for a dummy argument to have the allocatable attribute if you are going to do something related to its allocation status - query its status, reallocate it, deallocate it, etc.
Solution 2
Please also note that your allocatable dummy argument array
is declared with intent(in)
, which means its allocation status will be that of the associated actual argument (and it may not be changed during the procedure). The actual argument passed to your subroutine may be unallocated and therefore illegal to reference, even with an explicit interface. The compiler will not know this and the behaviour of inquiries like size
is undefined in such cases.
Hence, you first have to check the allocation status of array
with allocated(array)
before referencing its contents. I would further suggest to implement loops over the full array with lbound
and ubound
, since in general you can't be sure about array
's bounds:
subroutine subtest(array)
double precision, allocatable, intent(in) :: array(:,:)
integer :: iii, jjj
if(allocated(array)) then
print*, size(array, 1), size(array, 2)
do iii = lbound(array, 1), ubound(array, 1)
do jjj = lbound(array, 2), ubound(array, 2)
print*, array(iii,jjj)
enddo
enddo
endif
end subroutine
Solution 3
This is a simple example that uses allocatable dummy arguments with a module.
module arrayMod
real,dimension(:,:),allocatable :: theArray
end module arrayMod
program test
use arrayMod
implicit none
interface
subroutine arraySub
end subroutine arraySub
end interface
write(*,*) allocated(theArray)
call arraySub
write(*,*) allocated(theArray)
end program test
subroutine arraySub
use arrayMod
write(*,*) 'Inside arraySub()'
allocate(theArray(3,2))
end subroutine arraySub
Nordico
Updated on July 09, 2022Comments
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Nordico almost 2 years
The following code is returning a Segmentation Fault because the allocatable array I am trying to pass is not being properly recognized (size returns 1, when it should be 3). In this page (http://www.eng-tips.com/viewthread.cfm?qid=170599) a similar example seems to indicate that it should work fine in F95; my code file has a .F90 extension, but I tried changing it to F95, and I am using gfortran to compile.
My guess is that the problem should be in the way I am passing the allocatable array to the subroutine; What am I doing wrong?
!%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%! PROGRAM test !%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%! IMPLICIT NONE DOUBLE PRECISION,ALLOCATABLE :: Array(:,:) INTEGER :: iii,jjj ALLOCATE(Array(3,3)) DO iii=1,3 DO jjj=1,3 Array(iii,jjj)=iii+jjj PRINT*,Array(iii,jjj) ENDDO ENDDO CALL Subtest(Array) END PROGRAM !%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%! SUBROUTINE Subtest(Array) DOUBLE PRECISION,ALLOCATABLE,INTENT(IN) :: Array(:,:) INTEGER :: iii,jjj PRINT*,SIZE(Array,1),SIZE(Array,2) DO iii=1,SIZE(Array,1) DO jjj=1,SIZE(Array,2) PRINT*,Array(iii,jjj) ENDDO ENDDO END SUBROUTINE !%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%!
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sigma over 11 yearsNote: Added this as a new answer because I can't comment on others yet. It's more of an extension to IanH's answer that I think is important, since this subtlety is also missed in xwb's post at eng-tips.com. I didn't want to barge in with a big edit; feel free to merge this into one answer though.
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Nordico over 11 yearsubound would seem to to have the same effect as Size; what is the difference? And the use of lbound is in case an array starts with index higher than 1? can that happen?
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Nordico over 11 yearsThanks, this was my problem. I knew that some functions (don't remember the name they had, but I think they were the ones that changed the input parameters) needed explicit interfaces, but didn't know allocation was the same. And yes, the code was made for the purpose of debugging my real code.
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sigma over 11 years
size
gives the total number of elements of an array (without a dim argument) or the number along any dimension (with a dim argument). You may allocate array with bounds(-2:0, -2:0)
and the size will still be 3 along each dimension, butarray(1:3, 1:3)
is undefined. This is in contrast to a non-allocatable dummy array with assumed shape, where the lower bound is indeed assumed to be 1 if not specified.