How to pass dictionary items as function arguments in python?

Question

My code

1st file:

data = {'school':'DAV', 'standard': '7', 'name': 'abc', 'city': 'delhi'}
my_function(*data)

2nd file:

my_function(*data):
    schoolname  = school
    cityname = city
    standard = standard
    studentname = name

in the above code, only keys of "data" dictionary were get passed to my_function(), but i want key-value pairs to pass. How to correct this ?

I want the my_function() to get modified like this

my_function(school='DAV', standard='7', name='abc', city='delhi')

and this is my requirement, give answers according to this

EDIT: dictionary key class is changed to standard

Solution 1

If you want to use them like that, define the function with the variable names as normal:

def my_function(school, standard, city, name):
    schoolName  = school
    cityName = city
    standardName = standard
    studentName = name

Now you can use ** when you call the function:

data = {'school':'DAV', 'standard': '7', 'name': 'abc', 'city': 'delhi'}

my_function(**data)

and it will work as you want.

P.S. Don't use reserved words such as class.(e.g., use klass instead)

Solution 2

*data interprets arguments as tuples, instead you have to pass **data which interprets the arguments as dictionary.

data = {'school':'DAV', 'class': '7', 'name': 'abc', 'city': 'pune'}


def my_function(**data):
    schoolname  = data['school']
    cityname = data['city']
    standard = data['class']
    studentname = data['name']

You can call the function like this:

my_function(**data)

Solution 3

You can just pass it

def my_function(my_data):
    my_data["schoolname"] = "something"
    print my_data

or if you really want to

def my_function(**kwargs):
    kwargs["schoolname"] = "something"
    print kwargs

Comments

[Torxed]

Don't use variable names that are default objects in Python, such as the word class.

[pfabri]

...and this is my requirement, give answers according to this -- Ugh, a bit harsh. But a good question, nonetheless.

[stason]

@pfabri, it's quite clear from reading the question that English is not user's native language, so it's very possible that the harshness was unintended and that's just how they translated it to English.

[Patrick]

i have this line def my_function(*data), modify your code according to this line

[markcial]

you mean to recompile whole python interpreter to work like you want it to work?

[Patrick]

@markcial is there any way to implement in code as i like ?

[markcial]

@Patrick Not a chance, the only way is the one that RemcoGerlih proposed. He has a working sample of code, yours has failed, then is logical to follow their guidelines

[Patrick]

@RemcoGerlich its giving me error in def my_function(..) line for TypeError: my_function() got an unexpected keyword argument 'school'

[RemcoGerlich]

Then you didn't put 'school' in the arguments of the function.

[Mayank Choudhary]

Hello @RemcoGerlich and the rest, is there a way to pass values of only selected keys in a dictionary as parameters to a function?

[RemcoGerlich]

@MayankChoudhary: either first construct a new dictionary with only the selected keys and pass it with **, or just do my_function(mykey1=mydict["mykey1"], ...). There is no automatic way to call a function like that.

[Mayank Choudhary]

@RemcoGerlich : Thought so. Was wondering if you had something up your sleeve. :-) Thank you for your reply. I went about creating a new dictionaries.

[babygame0ver]

made my day :-)

[Falk Schuetzenmeister]

There is a fundamental difference between the two. The first passes a reference the second copies the data. If you pass a reference and the dictionary gets changed inside the function it will be changed outside the function as well which can cause very bad side effects.