How to plot a circle in Matlab?

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Solution 1

Don't laugh, but the easiest would be to use the rectangle function, indeed ;)

%// radius
r = 2;

%// center
c = [3 3];

pos = [c-r 2*r 2*r];
rectangle('Position',pos,'Curvature',[1 1])
axis equal

but set the curvature of the rectangle to 1!

The position vector defines the rectangle, the first two values x and y are the lower left corner of the rectangle. The last two values define width and height of the rectangle.

pos = [ [x y] width height ]

The lower left corner of your circle - yes, this circle has corners, imaginary ones though - is the center c = [3 3] minus the radius r = 2 which is [x y] = [1 1]. Width and height are equal to the diameter of the circle, so width = 2*r; height = width;

enter image description here


In case you don't like the smoothness of the above solution, there is no way around using the obvious way of drawing an actual circle by use of trigonometric functions.

%// number of points
n = 1000;

%// running variable
t = linspace(0,2*pi,n);

x = c(1) + r*sin(t);
y = c(2) + r*cos(t);

%// draw line
line(x,y)

%// or draw polygon if you want to fill it with color
%// fill(x,y,[1,1,1])
axis equal

enter image description here

Solution 2

If you want a circle that is not rectangle you can use annotation

center = [3, 4];
r = 2;
pos = [center-r, 2*r 2*r];
annotation('ellipse', pos );
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Hannah
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Hannah

Updated on July 05, 2022

Comments

  • Hannah
    Hannah almost 2 years

    I would like to know how can I graph circles in Matlab knowing the center and radius? I have tried circles() which does not seem to work because my Matlab version does not have it. I know I can use the Rectangle function to do so but it is a rather complex way of doing it as I would need to work out the leftmost point everytime.

    Isn't there a more simple way for me to draw a circle JUST knowing center and radius?