How to print text between two line numbers into a new file in UNIX

Question

I have a file like this (numbers on first column is line number)

30.<unit id=20>
31....
32.</unit>
33.<unit id=40?
34....
35.</unit>
36<unit id=20>
37...
38.</unit>
39.<unit id=40?
40....
41</unit>

I want to print lines between two line numbers, say 32 and 39. How can I accomplish this in Unix?
I'm new to unix. Note: I don't want perl scripts please.

Solution 1

use sed

sed -n '/^32/,/^39/p' file

Solution 2

Another way with sed:

 sed -n '32,39p' filename

Solution 3

I guess you should try this

sed '32,39!d' input > output

Solution 4

sed -n '32,39p' input > output

Note that this ignores your line numbering and simply prints lines 32 through 39. If you want to match the strings, use something like Fredrik's proposed solution.

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Comments

[Siva]

Thanks. There is small change now. Consider I don't have to manually input line numbers. I have a file like this: 13|20 35|45 75|96 546|633 I need a script for read this file for the line numbers and each of them in a new file. Thanks.

[Siva]

Thanks. There is small change now. Consider I don't have to manually input line numbers. I have a file like this: 13|20 35|45 75|96 546|633 I need a script for read this file for the line numbers and each of them in a new file. Thanks.

[Siva]

Thanks. There is small change now. Consider I don't have to manually input line numbers. I have a file like this: 13|20 35|45 75|96 546|633 I need a script for read this file for the line numbers and each of them in a new file. Thanks.

[Fredrik Pihl]

@Siva - Upvote the answers to this question that you like. Mark one as the most appropriate answer (green check mark) and then post a new question

[DontVoteMeDown]

Please add some explanation to your answer.

[frazras]

This somehow fails the answer with the highest votes work