How to remove all non-alphabetic characters from a string?
Solution 1
One way to remove non-alphabetic characters in a string is to use regular expressions [1].
>>> import re
>>> re.sub(r'[^a-z]', '', "lol123\t")
'lol'
EDIT
The first argument r'[^a-z]'
is the pattern that captures what will removed (here, by replacing it by an empty string ''
). The square brackets are used to denote a category (the pattern will match anything in this category), the ^
is a "not" operator and the a-z
denotes all the small caps alphabetiv characters. More information here:
https://docs.python.org/3/library/re.html#regular-expression-syntax
So for instance, to keep also capital letters and spaces it would be:
>>> re.sub(r'[^a-zA-Z ]', '', 'Lol !this *is* a3 -test\t12378')
'Lol this is a test'
However from the data you give in your question the exact process you need seems to be a bit more complicated than just "getting rid of non-alphabetical characters".
Solution 2
You can use filter
:
import string
print(''.join(filter(lambda character: character in string.ascii_letters + string.digits, '(ABC), DEF!'))) # => ABCDEF
Related videos on Youtube
A. Domni
Updated on June 04, 2022Comments
-
A. Domni almost 2 years
I have been working on a program which will take a hex file, and if the file name starts with "CID", then it should remove the first 104 characters, and after that point there is a few words. I also want to remove everything after the words, but the problem is the part I want to isolate varies in length.
My code is currently like this:
y = 0 import os files = os.listdir(".") filenames = [] for names in files: if names.endswith(".uexp"): filenames.append(names) y +=1 print(y) print(filenames) for x in range(1,y): filenamestart = (filenames[x][0:3]) print(filenamestart) if filenamestart == "CID": openFile = open(filenames[x],'r') fileContents = (openFile.read()) ItemName = (fileContents[104:]) print(ItemName)
Input Example file (pulled from HxD):
.........................ýÿÿÿ................E.................!...1AC9816A4D34966936605BB7EFBC0841.....Sun Tan Specialist.................9.................!...9658361F4EFF6B98FF153898E58C9D52.....Outfit.................D.................!...F37BE72345271144C16FECAFE6A46F2A.....Don't get burned............................................................................................................................Áƒ*ž
I have got it working to remove the first 104 characters, but I would also like to remove the characters after 'Sun Tan Specialist', which will differ in length, so I am left with only that part.
I appreciate any help that anyone can give me.
-
user3483203 almost 6 yearsYour question title is "remove non-alphabetic characters from a string". From the content of your question, it seems there are many more requirements thatn just that. Please clarify with a sample input, desired output, and a minimal reproducible example
-
A. Domni almost 6 yearsI have added an example file and what I would like the output to be
-
user3483203 almost 6 yearsSo what is your desired output? Just
Sun Tan Specialist
? -
user3483203 almost 6 yearsTry something like
re.sub(r'(.*?)(\..*)', r'\1', s[104:])
-
A. Domni almost 6 yearsAt this point yes, but ideally I would like: "Sun Tan Specialist | Don't get burned"
-
user3483203 almost 6 yearsBut why not
Outfit D
then? -
A. Domni almost 6 yearsBecause 'Outfit' will be present for all files beginning with 'CID' and that 'D' isn't relevant. Also using re.sub, I ,managed to get this as the output: "Sun Tan SpecialistFEFFBFFECDOutfitDFBECFECAFEAFADont get burned", but I don't want those sets of letters like 'FEFFBFFECD'
-
-
A. Domni almost 6 yearsThis may be a possibility, however I also want to keep capital letters and spaces, how would I do this?