How to run a csh script from a sh script

Question

I was wondering if there is a way to source a csh script from a sh script. Below is an example of what is trying to be implemented:

script1.sh:

#!/bin/sh

source script2

script2:

#!/bin/csh -f

setenv TEST 1234
set path = /home/user/sandbox

When I run sh script1.sh, I get syntax errors generated from script2 (expected since we are using a different Shebang). Is there a way I can run script2 through script1?

Solution 1

Instead of source script2 run it as:

csh -f script2

Solution 2

Since your use case depends on retaining environment variables set by the csh script, try adding this to the beginning of script1:

#!/bin/sh

if [ "$csh_executed" -ne 1 ]; then
    csh_executed=1 exec csh -c "source script2;
                                exec /bin/sh \"$0\" \"\$argv\"" "$@"
fi

# rest of script1

If the csh_executed variable is not set to 1 in the environment, run a csh script that sources script2 then executes an instance of sh, which will retain the changes to the environment made in script2. exec is used to avoid creating new processes for each shell instance, instead just "switching" from one shell to the next. Setting csh_executed in the environment of the csh command ensures that we don't get stuck in a loop when script1 is re-executed by the csh instance.

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Unfortunately, there is one drawback that I don't think can be fixed, at least not with my limited knowledge of csh: the second invocation of script1 receives all the original arguments as a single string, rather than a sequence of distinct arguments.

Solution 3

You don't want source there; it runs the given script inside your existing shell, without spawning a subprocess. Obviously, your sh process can't run something like that which isn't a sh script.

Just call the script directly, assuming it is executable:

script2