How to send x-www-form-urlencoded in a post request in webclient?

18,261

Solution 1

You can use UploadString() method on WebClient class like

string data = "name=john&age=20&city=Uganda";
using (WebClient client = new WebClient())
{
    client.Headers[HttpRequestHeader.ContentType] = "application/x-www-form-urlencoded";
    string result = client.UploadString(url of api resource, data);
}

Solution 2

        HttpClient client = new HttpClient();

        HttpContent content = new FormUrlEncodedContent(
            new List<KeyValuePair<string, string>>()
            );

        content.Headers.ContentType = new MediaTypeHeaderValue("application/x-www-form-urlencoded");
        content.Headers.ContentType.CharSet = "UTF-8";
        client.DefaultRequestHeaders.ExpectContinue = false;
        HttpResponseMessage response = await client.PostAsync(new Uri(https://some url...), content);

hope this helps.. since HttpClient is latest also lean towards restapi better..

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SkrtOnDiscord
Author by

SkrtOnDiscord

Updated on June 28, 2022

Comments

  • SkrtOnDiscord
    SkrtOnDiscord almost 2 years

    I know I can send json but I couldn't find how to send x-www-form-urlencoded. I don't know what to try as I couldn't find anything.

    WebClient wc = new WebClient();
    
    
    string data = "channel_id=+12039273888&channel_type=phone&channel_verification=514950";
    
    wc.Headers[HttpRequestHeader.ContentType] = "application/x-www-form-urlencoded";
    
    string result = wc.UploadString("http://3.86.171.88/api/login", data);
    
    System.Console.WriteLine(result);
    
  • SkrtOnDiscord
    SkrtOnDiscord almost 5 years
    i try to add that in my code and i get a 402 error - unprocessable indetitity.