how to sort date in descending order using comparator

Question

I have a bean object testBean with getter setter and methods.I am retrieving the results from the database and storing it in a TreeMap

The Output of the Map will look like this:

{Student1 = [testBean[Dept=Science,ID=12,grade=A,Date=12-Jan-2013]]
            [testBean[Dept=Science,ID=12,grade=B,Date=14-Mar-2013]]

{Student2 = [testBean[Dept=Science,ID=02,grade=A,Date=12-Jan-2013]]
            [testBean[Dept=Science,ID=02,grade=A,Date=14-Mar-2013]]

I need the Output to be arranged in Descending order so that the latest date comes first. So I am using a comparator to sort the date:

public int DateCompare(Object studentObj, Object anotherStudentObj) {
    SimpleDateFormat dateFormat = new SimpleDateFormat("dd-MMM-yyyy");
    String value = ((testBean) studentObj).getDateTmTrans();
    String value1 = ((testBean) anotherStudentObj).getDateTmTrans();
    int retVal = 0;

    try {

        Date firstDate = dateFormat.parse(value);
        Date secondDate = dateFormat.parse(value1);     
        retVal = firstDate.compareTo(secondDate);

    } catch (ParseException e) {
        e.printStackTrace();
    }       
    return 0;
}

But I couldn't able to sort the date in descending order. Is there any solution to get the desired output?

Any suggestions are welcome

Thanks in advance

Solution 1

But i couldn't able to sort the date in descending order.

Two easy options:

• You could just reverse your comparison yourself, using secondDate.compareTo(firstDate). (I assume that in your real code you're actually returning retVal; it's ignored in your posted code.)
• Call Collections.reverseOrder(Comparator) to create a comparator with the reverse order of the original one.

Solution 2

Instead of comparing firstDate against secondDate, compare secondDate against firstDate:

retVal = secondDate.compareTo(firstDate);

And don't forget to return retVal instead of 0 ;)