How to Submit Form into Bootstrap Modal (send POST method into Modal) Laravel
Well it has taken me some time but I think I found an answer to your question, or at least this solution can give you a good clue on how to continue with what you are doing.
First index.php: Here you need to have your form with an input field and one button, which we will call modal, and submit form (using Ajax for post)
<form id="form" method="post">
<div id="userDiv"><label>UserId</label>
<input type="text" name="userId" id="userId" placeholder="UserId"/> <br></div>
<button type="button" id="btn" class="btn btn-info" data-toggle="modal" data-target="#myModal">Send Data</button>
</form>
Then you need a modal where you will put content from remote page. In modal-body you add one more div tag with id="bingo" to locate him easy :) like this:
<div class="modal fade" id="myModal" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-label="Close"><span aria-hidden="true">×</span></button>
<h4 class="modal-title" id="myModalLabel">MyModal</h4>
</div>
<div class="modal-body">
<div id="bingo"></div>
</div>
</div>
</div>
</div>
This page also needs to have a script tag which will do the job. Important it must be placed after the script tag where you load the jquery file.
<script>
$(document).ready(function(){
$("#btn").click(function(){
var vUserId = $("#userId").val();
if(vUserId=='')
{
alert("Please enter UserId");
}
else{
$.post("result.php", //Required URL of the page on server
{ // Data Sending With Request To Server
user:vUserId,
},
function(response,status){ // Required Callback Function
$("#bingo").html(response);//"response" receives - whatever written in echo of above PHP script.
$("#form")[0].reset();
});
}
});
});
</script>
And last but not the least result.php:
<?php
if($_POST["user"])
{
$user = $_POST["user"];
// Here, you can also perform some database query operations with above values.
echo "Your user id is: ". $user;
}
?>
P.S. I hope I didn't mess somewhere with ids, variables or similar because I tried to adjust the solution to your example. I hope this is what you need, or at least this will be a clue to accomplish your task. Still think that this could be done on one page but it was interesting for me to try to find a way to make this work... GL!
![ErcanE](https://i.stack.imgur.com/0RaqB.png?s=256&g=1)
ErcanE
Updated on January 18, 2020Comments
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ErcanE over 4 years
I have been trying for 2 days but still no luck!
I want to
- Submit Form from index.php to result.php
- Show result.php inside Modal while index.php is open! (without closing index.php)
here is example code!
index.php
<form id="myform" method="post" action="result.php" target="_blank"> <input type="text" name="userId" id="userId"/> <input id="button" type="submit"/> </form>
result.php
<div id="resultModal" class="modal fade" tabindex="-1"> <div class="modal-dialog"> <div class="modal-content"> <div class="modal-header"> <button type="button" class="close" data-dismiss="modal" aria-hidden="true"> <i class="fa fa-times-circle"></i>ESC</button> <h4 class="modal-title">Show Result </h4> </div> <div class="modal-body"> </div> </div> </div> </div>
In Modal body
<?php $selectedId = $_POST['userId']; echo $selectedId; ?>
And JQuery
<script type="text/javascript"> $('#myForm').on('submit', function(ev) { var userId = $('#userId').find("input").val(); $.ajax({ type: 'POST', url : $(this).attr('action'), data: userId, success: function () { // alert('form was submitted'); } }); }); </script>
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ErcanE over 9 yearsThank you for your time Aleksandar! Just because I am working on Laravel project that reason I couldn't show all my code here.I couldn't make your code working but maybe I am missing something! So I will check deeply.
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Aleksandar Miladinovic over 9 yearsYou're welcome. Well it's work fine for me, i will check if i miss something one more time but i think i didn't... I hope you will make it work. I have problem with <script> tag at first i put <script src=jquer> after this script with ajax code accidentally so it's caused me a problem and take some time, i believe it's something small like that. So, if you already didn't place it like that, first <script src=jquer.js> than <script>Ajax code</script> than <script src=bootstrap.js>....
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ErcanE over 9 yearsThere is no problem to load script and modal pop up window.But I cant get remote content.Only empty modal window loading which is located in index.php
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Aleksandar Miladinovic over 9 yearsI just test it and it's work just fine, is there a way to sand you my php source files? I'm new here so i don't know if it's possible.
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ErcanE over 9 yearsI didn't upload here because of Laravel project.So not many people use Laravel. I ll find the way to show you source code, I will be available lately.Thank you again Aleksandar!
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Aleksandar Miladinovic over 9 yearsAnd again you're welcome. Sorry for my English I want to send my index.php and result.php to you so you can check what's happened there to compere code... :) sorry for misunderstanding
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ErcanE over 9 yearsSo sorry my bad! I was in rush so couldn't read carefully! Here is one of the best online code tester jsfiddle.net Regards
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Aleksandar Miladinovic over 9 yearsI can't there write php code so here is dropbox link link to this two file, download them and try to see if it's work...
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ErcanE over 9 yearsLet us continue this discussion in chat.