How to test a react component that is dependent on useContext hook?

74,622

Solution 1

In general, using hooks shouldn't change testing strategy much. The bigger issue here actually isn't the hook, but the use of context, which complicates things a bit.

There's a number of ways to make this work, but only approach I've found that works with 'react-test-renderer/shallow' is to inject a mock hook:

import ShallowRenderer from 'react-test-renderer/shallow';

let realUseContext;
let useContextMock;
// Setup mock
beforeEach(() => {
    realUseContext = React.useContext;
    useContextMock = React.useContext = jest.fn();
});
// Cleanup mock
afterEach(() => {
    React.useContext = realUseContext;
});

test("mock hook", () => {
    useContextMock.mockReturnValue("Test Value");
    const element = new ShallowRenderer().render(
        <MyComponent />
    );
    expect(element.props.children).toBe('Test Value');
});

This is a bit dirty, though, and implementation-specific, so if you're able to compromise on the use of the shallow renderer, there's a few other options available:

Non-shallow render

If you're not shallow rendering, you can just wrap the component in a context provider to inject the value you want:

import TestRenderer from 'react-test-renderer';

test("non-shallow render", () => {
    const element = new TestRenderer.create(
        <NameContext.Provider value="Provided Value">
            <MyComponent />
        </NameContext.Provider>
    );
    expect(element.root.findByType("div").children).toEqual(['Provided Value']);
});

(Disclaimer: this should work, but when I test it, I'm hitting an error which I think is an issue in my setup)

Shallow render with Enzyme and Dive

As @skyboyer commented, enzyme's shallow renderer supports .dive allowing you to deeply renderer a part of an otherwise shallow rendered component:

import { shallow } from "./enzyme";

test("enzyme dive", () => {
    const TestComponent = () => (
        <NameContext.Provider value="Provided Value">
            <MyComponent />
        </NameContext.Provider>
    );
    const element = shallow(<TestComponent />);
    expect(element.find(MyComponent).dive().text()).toBe("Provided Value");
});

Use ReactDOM

Finally, the Hooks FAQ has an example of testing hooks with ReactDOM, which works as well. Naturally, using ReactDOM means this is also a deep render, not shallow.

let container;
beforeEach(() => {
    container = document.createElement('div');
    document.body.appendChild(container);
});

afterEach(() => {
    document.body.removeChild(container);
    container = null;
});

test("with ReactDOM", () => {
    act(() => {
        ReactDOM.render((
            <NameContext.Provider value="Provided Value">
                <MyComponent />
            </NameContext.Provider>
        ), container);
    });

    expect(container.textContent).toBe("Provided Value");
});

Solution 2

I tried to use Enzyme + .dive, but when diving, it does not recognize the context props, it gets the default ones. Actually, it is a known issue by the Enzyme team. Meanwhile, I came up with a simpler solution which consists in creating a custom hook just to return useContext with your context and mocking the return of this custom hook on the test:

AppContext.js - Creates the context.

import React, { useContext } from 'react';

export const useAppContext = () => useContext(AppContext);

const defaultValues = { color: 'green' };
const AppContext = React.createContext(defaultValues);

export default AppContext;

App.js — Providing the context

import React from 'react';
import AppContext from './AppContext';
import Hello from './Hello';

export default function App() {
  return (
    <AppContext.Provider value={{ color: 'red' }}>
      <Hello />
    </AppContext.Provider>
  );
}

Hello.js - Consuming the context

import React from 'react';
import { useAppContext } from './AppContext';

const Hello = props => {
  const { color } = useAppContext();
  return <h1 style={{ color: color }}>Hello {color}!</h1>;
};

export default Hello;

Hello.test.js - Testing the useContext with Enzyme shallow

import React from 'react';
import { shallow } from 'enzyme';
import * as AppContext from './AppContext';

import Hello from './Hello';

describe('<Hello />', () => {
  test('it should mock the context', () => {
    const contextValues = { color: 'orange' };
    jest
      .spyOn(AppContext, 'useAppContext')
      .mockImplementation(() => contextValues);
    const wrapper = shallow(<Hello />);
    const h1 = wrapper.find('h1');

    expect(h1.text()).toBe('Hello orange!');
  });
});

Check the full Medium article out https://medium.com/7shifts-engineering-blog/testing-usecontext-react-hook-with-enzyme-shallow-da062140fc83

Solution 3

Or if you're testing your component in isolation without mounting the parent components you can simply mocking useContext:

jest.mock('react', () => {
  const ActualReact = jest.requireActual('react')
  return {
    ...ActualReact,
    useContext: () => ({ }), // what you want to return when useContext get fired goes here
  }
})

Solution 4

Old post but if it helps someone this is how I got it to work

import * as React from 'react';
import { shallow } from 'enzyme';

describe('MyComponent', () => {
  it('should useContext mock and shallow render a div tag', () => {
    jest.spyOn(React, 'useContext').mockImplementation(() => ({
      name: 'this is a mock context return value'
    }));

    const myComponent = shallow(
      <MyComponent
        props={props}
      />).dive();

    expect(myComponent).toMatchSnapShot();
  });
});

Solution 5

To complete the above accepted answer, for non-shallow rendering, I slightly tweaked the code to simply surround my component with the context

import { mount } from 'enzyme';
import NameContext from './NameContext';

test("non-shallow render", () => {
    const dummyValue = {
      name: 'abcd',
      customizeName: jest.fn(),
      ...
    }; 
    const wrapper = mount(
        <NameContext.Provider value={dummyValue}>
            <MyComponent />
        </NameContext.Provider>
    );

    // then use  
    wrapper.find('...').simulate('change', ...);
    ...
    expect(wrapper.find('...')).to...;
});
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bensampaio

Updated on February 27, 2022

Comments

  • bensampaio
    bensampaio over 2 years

    I have a component that uses useContext and then its output is dependent on the value in the context. A simple example:

    import React, { useContext } from 'react';
    
    const MyComponent = () => {
      const name = useContext(NameContext);
    
      return <div>{name}</div>;
    };
    

    When testing this component with the shallow renderer from react and jest snapshots. How can I change the value of NameContext?

    • skyboyer
      skyboyer over 5 years
      you may just wrap your component with <NameContext.Provider>: github.com/facebook/react/issues/7905
    • bensampaio
      bensampaio over 5 years
      That doesn't seem to work with shallow rendering because then it won't render the internals of my component. When I tried that I got a snapshot like: <NameContext.Provider value={'Paul'}><MyComponent/></NameContext.Provider> instead of <div>Paul</div>
    • skyboyer
      skyboyer over 5 years
      yes, here .dive() is made for
    • bensampaio
      bensampaio over 5 years
      .dive() is from enzym but there is nothing similar for the react shallow renderer.
    • skyboyer
      skyboyer over 5 years
      yes, you're right, missed that part
    • TToprak1
      TToprak1 over 4 years
  • bensampaio
    bensampaio over 5 years
    I like the mock idea. It didn't cross my mind. Not as elegant as the other approaches but more elegant than the approaches I tried. I love the deep function idea, I hope they will bring it to react shallow renderer at some point. Thanks for your answer!
  • Yugandhar Pathi
    Yugandhar Pathi about 5 years
    I am facing a challenge when using Enzyme, I exactly followed the mock idea you have shown but the problem is by the time I check my condition component is not rendered with context value. Note : I update my component with context value in useEffect.
  • Sumanth madey
    Sumanth madey almost 5 years
    I have followed same example. i see actual default values are mocked every time i run the test. Mock values not rendered, can you please let me know what is missing.
  • Shlang
    Shlang about 4 years
    The accepted answer contains the exaple for non-shallow rendering
  • HomelessGruesomeMoose
    HomelessGruesomeMoose about 4 years
    Hi, if you look carefully it's not quite the same (uses TestRenderer) and gave me an error when I tried it. Hence why I shared this.
  • Chris
    Chris almost 4 years
    Warning: this replaces useContext everywhere and so breaks any part of the thing under test that also uses useContext, e.g. styled-components. Alex Andrade's answer will allow you to isolate which uses of useContext you'd like to mock.
  • Anna
    Anna almost 4 years
    I implemented this and it's not working for me. wrapper returns as undefined =/ codesandbox.io/s/react-usecontext-jest-test-9r93g?file=/src/‌​…
  • KeitelDOG
    KeitelDOG about 3 years
    @Chris you can check the value.displayName to see if it's from StylesContext, ThemeContext in case of material ui if you have useContext: value => {...}, and return accordingly or leave the original function.
  • Menai Ala Eddine - Aladdin
    Menai Ala Eddine - Aladdin almost 3 years
    What if the value is an object that contains a property and a function.
  • Menai Ala Eddine - Aladdin
    Menai Ala Eddine - Aladdin almost 3 years
    What if MyComponent contains a child?
  • Akhil Ravindran
    Akhil Ravindran about 2 years
    I am getting the following error - Cannot assign to 'useContext' because it is a read-only property.