How to use Java to download a mp3 file online?
Solution 1
Using old-school Java IO, but you can map this to the NIO method you are using. Key thing is use of URLConnection.
URLConnection conn = new URL("http://online1.tingclass.com/lesson/shi0529/43/32.mp3").openConnection();
InputStream is = conn.getInputStream();
OutputStream outstream = new FileOutputStream(new File("/tmp/file.mp3"));
byte[] buffer = new byte[4096];
int len;
while ((len = is.read(buffer)) > 0) {
outstream.write(buffer, 0, len);
}
outstream.close();
Solution 2
FileInputStream is used to access local files only. If you want to access the content of an URL you can setup an URLConnection or use something like this:
URL myUrl = new URL("http://online1.tingclass.com/lesson/shi0529/43/32.mp3");
InputStream myUrlStream = myUrl.openStream();
ReadableByteChannel myUrlChannel = Channels.newChannel(myUrlStream);
FileChannel destinationChannel=new FileOutputStream(To_File).getChannel();
destinationChannel.transferFrom(myUrlChannel, 0, sizeOf32MP3);
Or more simply just make a BufferedInputStream from myUrlStream and cycle the read/write operation until EOF is found on myUrlStream.
Cheers, Andrea
Solution 3
When you create a FileInputStream
, you always access your local filesystem. Instead, you should use a URLConnection
for accessing files over HTTP.
The indicator for this is that the forward slashes /
have turned into backward slashes \
.
Frank
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Updated on July 11, 2022Comments
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Frank almost 2 years
I used the following method to download an mp3 file at : http://online1.tingclass.com/lesson/shi0529/43/32.mp3
But I got the following error :
java.io.FileNotFoundException: http:\online1.tingclass.com\lesson\shi0529\43\32.mp3 (The filename, directory name, or volume label syntax is incorrect)
public static void Copy_File(String From_File,String To_File) { try { FileChannel sourceChannel=new FileInputStream(From_File).getChannel(); FileChannel destinationChannel=new FileOutputStream(To_File).getChannel(); sourceChannel.transferTo(0,sourceChannel.size(),destinationChannel); // or // destinationChannel.transferFrom(sourceChannel, 0, sourceChannel.size()); sourceChannel.close(); destinationChannel.close(); } catch (Exception e) { e.printStackTrace(); } }
Yet if I do it from a browser by hand, the file is there, I wonder why it didn't work, and what's the right way to do it ?
Frank