How to use Strtok for tokenizing a Const char*?

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Solution 1

Since strtok actually writes to your string, you need to make a writable copy of it to tokenize;

char* copy = strdup(myReadonlyString);
...tokenize copy...
free(copy);

Solution 2

Declare it as an array:

char tokenedStr[] = "OpenStack:OpenStack1";

if not possible, copy it to a char array.

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the_naive
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the_naive

Updated on June 06, 2022

Comments

  • the_naive
    the_naive about 2 years

    I have a const char* variable which may have a value like "OpenStack:OpenStack1". I want to tokenize this const char* using strtok where the delimiter(which is of a const char* type) is ":" . But the problem is strtok is of following type: char * strtok ( char * str, const char * delimiters );

    Which means I can't use const char* for the first input as it has to be char*. Could you say me how I can convert this const char* into char*?

    Thank you.

  • ManuelAtWork
    ManuelAtWork over 8 years
    A c++ way of making a copy would be std::vector<char> copy(myReadonlyString, myReadonlyString+strlen(myReadonlyString));. You can then tokenize copy->data(). The compiler will de-allocate the copy automatically whenever it goes out of scope.
  • Rob Kennedy
    Rob Kennedy about 6 years
    @Manuel, the value you've stored in copy isn't null-terminated. Use strlen(myReadonlyString) + 1 to ensure the input's terminator is included in the vector.