How to write a xpath to match all elements except a particular element

26,413

Solution 1

I want to write a template that matches all nodes except ServiceNode i.e. NodeA to NodeX.

If by "node" you mean element, then use:

<xsl:template match="*[not(self::ServiceNode)]">

If by "node" you mean any node (of type element, text, comment, processing-instruction): use

<xsl:template match="node()[not(self::ServiceNode)]">

If you want only children of Document to be matched use:

<xsl:template match="Document/node()[not(self::ServiceNode)]">

If you want only children of the top element to be matched use:

<xsl:template match="/*/node()[not(self::ServiceNode)]">

Solution 2

You should better use this expression:

*[not(self::ServiceNode)]

As incorporated in an XSLT:

<xsl:stylesheet
    version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="text"/>

    <xsl:template match="/*">
        <xsl:apply-templates select="*[not(self::ServiceNode)]"/>
    </xsl:template>

    <xsl:template match="*">
        <xsl:value-of select="."/>
        <xsl:text>&#xA;</xsl:text>
    </xsl:template>

</xsl:stylesheet>

With this XML sample:

<Document>
    <NodeA>1</NodeA>
    <NodeB>2</NodeB>
    <ServiceNode>3</ServiceNode>
    <NodeX>4</NodeX>
</Document>

It will give a correct result:

1
2
4

Solution 3

<xsl:template match="Document/*[name() != 'ServiceNode']">

(or local-name() if you have to deal with namespaces)

Solution 4

You could use two templates:

<xsl:template match="Document/*">
   ...do something...
</xsl:template>


<xsl:template match="Document/ServiceNode" />

The later template will take priority, so the first template will match everything except ServiceNode.

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26,413
Unmesh Kondolikar
Author by

Unmesh Kondolikar

Updated on January 06, 2020

Comments

  • Unmesh Kondolikar
    Unmesh Kondolikar over 4 years

    I am writing an XSL transformation. I want to write a template which matches all the child elements of the document except one particular node. My xml looks like this -

    <Document>
        <NodeA></NodeA>
    
        <NodeB></NodeB>
    
        <ServiceNode></ServiceNode>
    
        <NodeX></NodeX>
    </Document>
    

    I want to write a template that matches all nodes except ServiceNode i.e. NodeA to NodeX. How to write this Xpath to get -

    <xsl:template match="ALL Nodex Except ServiceNode">
    
  • Chris Dolan
    Chris Dolan over 13 years
    I recommend testing in a live evaluator like whitebeam.org/library/guide/TechNotes/xpathtestbed.rhtm where you can paste expressions like //*[name()!="pet"]
  • Michael Kay
    Michael Kay over 13 years
    Correct. This is better than testing on name() or local-name(). In XPath 2.0 an alternative is (* except ServiceNode)
  • Admin
    Admin over 13 years
    I agree. Better than name().
  • Admin
    Admin over 13 years
    This could be useful in some cases, besides it doesn't answer this question properly.