incorrect number of dimensions and incorrect number of subscripts in array
77,073
You need to convert your data frames into matrices before you do the assignment:
l <- list(data.frame(x=1:2, y=3:4), data.frame(x=5:6, y=7:8))
arr <- array(dim=c(2, 2, 2))
arr[,,1] <- as.matrix(l[[1]])
arr[,,2] <- as.matrix(l[[2]])
arr
# , , 1
#
# [,1] [,2]
# [1,] 1 3
# [2,] 2 4
#
# , , 2
#
# [,1] [,2]
# [1,] 5 7
# [2,] 6 8
You can actually build the array in one line with the unlist
function applied to a list of the matrices you want to combine:
arr2 <- array(unlist(lapply(l, as.matrix)), dim=c(dim(l[[1]]), length(l)))
all.equal(arr, arr2)
# [1] TRUE
Author by
Admin
Updated on June 09, 2020Comments
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Admin almost 4 years
I am new to using R and thus my question might be a simple one, but nonetheless I have spent a lot of time trying to figure out what I am doing wrong and to no avail. I have discovered a lot of help on this site in the past week searching through other questions/answers (thank you!) but as someone new, it is often difficult to interpret other people's code.
I am trying to build a 3-dimensional array of multiple data files, each one with the same dimensions 57x57.
# read in 100 files Files = lapply(Sys.glob('File*.txt'), read.table, sep='\t', as.is=TRUE) # convert to dataframes Files = lapply(Files[1:100], as.data.frame) # check dimensions of first file (it's the same for all) dim(Files[[1]]) [1] 57 57 # build empty array Array = array(dim=c(57,57,100)) # read in the first data frame Array[,,1] = Files[1] # read in the second data frame Array[,,2] = Files[2] Error in Array[, , 2] = Files[2] : incorrect number of subscripts # if I check... Array[,,1] = Files[1] Error in Array[, , 1] : incorrect number of dimensions # The same thing happens when I do it in a loop: x = 0 for(i in 1:100){ Array[,,x+1] = Files[[i]] x = x + 1 } Error in Array[, , 1] = Files[[1]] : incorrect number of subscripts