Index autoincrement for Microsoft SQL Server 2008 R2
54,727
Solution 1
In SQL Server, it's not a separate datatype ("autoincrement") - but you can define an INT
column to be an IDENTITY
.
How are you creating your table - visual designer or T-SQL script??
In T-SQL, you would use:
CREATE TABLE dbo.MyTable(ID INT IDENTITY(1,1) ......
and in the visual table designer, you need to check:
It's an option for a column of type INT - you can define the seed (starting value) and the increment - typically both are set to 1.
Solution 2
If your table definition is like this,
....,
@id int,
....
change it to,
....
@id int identity(1,1),
....
This will create an identity column which starts id with 1 and keeps increasing it by one(i.e. step) as each record in the table is inserted.
Comments
-
Magnetic_dud about 4 years
I created a new table in SQL Server 2008 R2, and i would like that the index is on autoincrement. How to do that? There is no identity data type; i selected int
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ZygD over 13 yearsWhere does @id come into it please?
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Magnetic_dud over 13 yearsThanks a lot! I was using MS SQL Management Studio - visual designer