indexOf is not a function in Firefox, Opera but works in IE, indexOf alternative in javascript to test string contains?

Question

Getting an error using indexOf call in Javascript on Firefox and Opera. Works fine in IE.

Following is the error message:

Action

function anonymous(Grid, Row, Col, Event) { 
    return Grid.ActionShowPopupMenu(); 
} 

for event OnRightClick failed with exception: row.id.indexOf is not a function

I'm testing that a string contains another string in Javascript and using the indexOf function of a string. The calls however are being made in JQuery functions. Perhaps that is the reason for the problem? Is there an alternative to using indexOf in Javascript to test if a string contains another string? Is there a workaround for this problem?

Solution 1

String.indexOf is perfectly OK in all browsers. I assume the id property of your row object is no string (nor array, btw, because indexOf is also defined on arrays (except for IE))

Solution 2

indexOf is not okay for IE prior to IE9. If you want your code to work in ie < 9, you should define the method for non-compliant browsers in a common js file that can be dropped into every page. See this thread for more details. The code is taken from Mozilla

if (!Array.prototype.indexOf) {
    Array.prototype.indexOf = function (searchElement /*, fromIndex */ ) {
        "use strict";
        if (this == null) {
            throw new TypeError();
        }
        var t = Object(this);
        var len = t.length >>> 0;
        if (len === 0) {
            return -1;
        }
        var n = 0;
        if (arguments.length > 1) {
            n = Number(arguments[1]);
            if (n != n) { // shortcut for verifying if it's NaN
                n = 0;
            } else if (n != 0 && n != Infinity && n != -Infinity) {
                n = (n > 0 || -1) * Math.floor(Math.abs(n));
            }
        }
        if (n >= len) {
            return -1;
        }
        var k = n >= 0 ? n : Math.max(len - Math.abs(n), 0);
        for (; k < len; k++) {
            if (k in t && t[k] === searchElement) {
                return k;
            }
        }
        return -1;
    }
}