input() error - NameError: name '...' is not defined

854,760

Solution 1

TL;DR

input function in Python 2.7, evaluates whatever your enter, as a Python expression. If you simply want to read strings, then use raw_input function in Python 2.7, which will not evaluate the read strings.

If you are using Python 3.x, raw_input has been renamed to input. Quoting the Python 3.0 release notes,

raw_input() was renamed to input(). That is, the new input() function reads a line from sys.stdin and returns it with the trailing newline stripped. It raises EOFError if the input is terminated prematurely. To get the old behavior of input(), use eval(input())


In Python 2.7, there are two functions which can be used to accept user inputs. One is input and the other one is raw_input. You can think of the relation between them as follows

input = eval(raw_input)

Consider the following piece of code to understand this better

>>> dude = "thefourtheye"
>>> input_variable = input("Enter your name: ")
Enter your name: dude
>>> input_variable
'thefourtheye'

input accepts a string from the user and evaluates the string in the current Python context. When I type dude as input, it finds that dude is bound to the value thefourtheye and so the result of evaluation becomes thefourtheye and that gets assigned to input_variable.

If I enter something else which is not there in the current python context, it will fail will the NameError.

>>> input("Enter your name: ")
Enter your name: dummy
Traceback (most recent call last):
  File "<input>", line 1, in <module>
  File "<string>", line 1, in <module>
NameError: name 'dummy' is not defined

Security considerations with Python 2.7's input:

Since whatever user types is evaluated, it imposes security issues as well. For example, if you have already loaded os module in your program with import os, and then the user types in

os.remove("/etc/hosts")

this will be evaluated as a function call expression by python and it will be executed. If you are executing Python with elevated privileges, /etc/hosts file will be deleted. See, how dangerous it could be?

To demonstrate this, let's try to execute input function again.

>>> dude = "thefourtheye"
>>> input("Enter your name: ")
Enter your name: input("Enter your name again: ")
Enter your name again: dude

Now, when input("Enter your name: ") is executed, it waits for the user input and the user input is a valid Python function invocation and so that is also invoked. That is why we are seeing Enter your name again: prompt again.

So, you are better off with raw_input function, like this

input_variable = raw_input("Enter your name: ")

If you need to convert the result to some other type, then you can use appropriate functions to convert the string returned by raw_input. For example, to read inputs as integers, use the int function, like shown in this answer.

In python 3.x, there is only one function to get user inputs and that is called input, which is equivalent to Python 2.7's raw_input.

Solution 2

You are running Python 2, not Python 3. For this to work in Python 2, use raw_input.

input_variable = raw_input ("Enter your name: ")
print ("your name is" + input_variable)

Solution 3

Since you are writing for Python 3.x, you'll want to begin your script with:

#!/usr/bin/env python3

If you use:

#!/usr/bin/env python

It will default to Python 2.x. These go on the first line of your script, if there is nothing that starts with #! (aka the shebang).

If your scripts just start with:

#! python

Then you can change it to:

#! python3

Although this shorter formatting is only recognized by a few programs, such as the launcher, so it is not the best choice.

The first two examples are much more widely used and will help ensure your code will work on any machine that has Python installed.

Solution 4

I also encountered this issue with a module that was supposed to be compatible for python 2.7 and 3.7

what i found to fix the issue was importing:

from six.moves import input

this fixed the usability for both interpreters

you can read more about the six library here

Solution 5

You should use raw_input because you are using python-2.7. When you use input() on a variable (for example: s = input('Name: ')), it will execute the command ON the Python environment without saving what you wrote on the variable (s) and create an error if what you wrote is not defined.

raw_input() will save correctly what you wrote on the variable (for example: f = raw_input('Name : ')), and it will not execute it in the Python environment without creating any possible error:

input_variable = raw_input('Enter Your Name : ')
print("Your Name Is  : " + (input_variable))
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chillpenguin
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chillpenguin

Updated on March 10, 2022

Comments

  • chillpenguin
    chillpenguin about 2 years

    I am getting an error when I try to run this simple script:

    input_variable = input("Enter your name: ")
    print("your name is" + input_variable)
    

    Let's say I type in "dude", the error I am getting is:

      line 1, in <module>
        input_variable = input("Enter your name: ")
      File "<string>", line 1, in <module>
    NameError: name 'dude' is not defined
    

    I am running Mac OS X 10.9.1 and I am using the Python Launcher app that came with the install of Python 3.3 to run the script.

    • Kevin
      Kevin over 10 years
      Are you sure it's Python 3.3? I would expect input to behave this way, but only in 2.7. What does it say when you run python --version from a command prompt? Alternatively, what if you write import sys; print(sys.version) at the beginning of your script?
    • Wooble
      Wooble over 10 years
      You're not running Python 3. You're running Python 2, somehow (I'm not familiar with this "Python Launcher" app)
    • Hyperboreus
      Hyperboreus over 10 years
      Put as first line import sys and as second line print(sys.version_info) in order to ascertain which version you are using.
    • chillpenguin
      chillpenguin over 10 years
      I did what Kevin said and it is version 2.7.5! I'm not sure how though. I downloaded and installed version 3.3, in my applications folder there is a folder that is called "Python 3.3" inside that folder there is an app called "Python Launcher" and I am running my scripts by dragging and dropping them onto the Python Launcher app. How come I am still using 2.7 when I am using the 3.3 launcher app?
    • thefourtheye
      thefourtheye over 10 years
      @chillpenguin Please include in the question that you are using 2.7. Thats crucial to answer this question.
    • Wooble
      Wooble over 10 years
      @thefourtheye: The whole question is basically "why is Python Launcher running python 2 instead of, sensibly, Python 3", so... not really.
    • chillpenguin
      chillpenguin over 10 years
      I just edited my question to include that. I did not know that I was using 2.7.5 until I followed Kevin's instructions.
    • Wooble
      Wooble over 10 years
      @chillpenguin: check out the Preferences dialog for Python Launcher. Apparently it doesn't default to running the version it was installed with, which is... dumb. (I've never used it myself; I find using the Terminal is better...)
    • chillpenguin
      chillpenguin over 10 years
      Thank you Wooble. Right now under prefences it says "interpreter: /usr/bin/pythonw " Is that what I want to change? What do I change it to?
    • Cosine
      Cosine about 7 years
      #!/usr/bin/env python3 as first line
  • Spencer Goff
    Spencer Goff over 6 years
    raw_input fixed the issue for me
  • carthurs
    carthurs over 5 years
    But raw_input() isn't available in Python 3.
  • chepner
    chepner over 2 years
    If you need to support Python 2 and Python 3, you should be using the six library, which provides six.input. There's no reason to catch a NameError every single time you call input_compatible if you are using Python 3.
  • dux2
    dux2 over 2 years
    Sometimes you don't want to depend on any non standard packages, for example when writing a portable shell script, so this answer has it place and justification.
  • chepner
    chepner over 2 years
    That still doesn't excuse using a try statement every single time you try to call the function. raw_input isn't going to suddenly appear while your script is executing; it's either available at the beginning or not at all. Also, if you need compatibility between both versions, there is likely a lot of stuff you are going to need to accommodate, and it doesn't make sense not to use six.
  • dux2
    dux2 over 2 years
    Pardon @chepner, but I don't agree with you. First, you didn't provide a better alternative for use cases that require a portable solution and cannot use any non-standard package. Since you haven't, I edited my answer to include such. Second, while I normally agree with you that you shouldn't use try block for situation you can easily check in advance, in this case, it doesn't have any performance downside and looks cleaner than the alternative in my opinion.
  • chepner
    chepner over 2 years
    Not every problem can or should be solved with the standard library alone.
  • khelwood
    khelwood over 2 years
    __builtins__.__dict__.get("input") is None is never true. You could check if 'raw_input' in __builtins__.__dict__. Or you could just check sys.version_info to see which version of Python you're on.
  • dux2
    dux2 over 2 years
    @khelwood Thanks, modified it.
  • wjandrea
    wjandrea over 2 years
    raw_input is not defined in Python 3. Is that a typo of "Python 2"?