Insert at first position of a list in Python

329,860

Solution 1

Use insert:

In [1]: ls = [1,2,3]

In [2]: ls.insert(0, "new")

In [3]: ls
Out[3]: ['new', 1, 2, 3]

Solution 2

From the documentation:

list.insert(i, x)
Insert an item at a given position. The first argument is the index of the element before which to insert, so a.insert(0, x) inserts at the front of the list, and a.insert(len(a),x) is equivalent to a.append(x)

http://docs.python.org/2/tutorial/datastructures.html#more-on-lists

Share:
329,860

Related videos on Youtube

Fr0z3n7
Author by

Fr0z3n7

Updated on July 08, 2022

Comments

  • Fr0z3n7
    Fr0z3n7 almost 2 years

    How can I insert an element at the first index of a list? If I use list.insert(0, elem), does elem modify the content of the first index? Or do I have to create a new list with the first elem and then copy the old list inside this new one?