Is there a Matlab conditional IF operator that can be placed INLINE like VBA's IIF
Solution 1
There is no ternary operator in Matlab. You can, of course, write a function that would do it. For example, the following function works as iif
with n-d input for the condition, and with numbers and cells for the outcomes a
and b
:
function out = iif(cond,a,b)
%IIF implements a ternary operator
% pre-assign out
out = repmat(b,size(cond));
out(cond) = a;
For a more advanced solution, there's a way to create an inline function that can even do elseif, as outlined in this blog post about anonymous function shenanigans:
iif = @(varargin) varargin{2*find([varargin{1:2:end}], 1, 'first')}();
You use this function as
iif(condition_1,value_1,...,true,value_final)
where you replace the dots with any number of additional condition/value pairs.
The way this works is that it picks among the values the first one whose condition is true. 2*find(),1,'first')
provides the index into the value arguments.
Solution 2
How about simply using the fact that MATLAB automatically converts variable types when required by the operation? E.g., logical to double.
If your variables are scalar double, your code, I believe, can be replaced by
a = b + (c > 0) * c;
In this case, the operator (c > 0)
values 1
(logical type) whenever c > 0
and values to 0
otherwise.
Solution 3
Others have said already that there is no ternary ?:
operator in Matlab. As a solution I suggest this function, which takes three functions instead of values. Therefore the amount of unnecessary calculations is minimized and you can check conditions before starting calculations, e.g. if a value is really numeric, or finite, or nonzero:
function [ out ] = iif( condition, thenF, elseF, in, out)
%iif Implements the ternary ?: operator
% out = iif (@condition, @thenF, @elseF, in[, out])
%
% The result is equivalent to:
% condition(x) ? thenF(x) : elseF(x)
%
% The optional argument out serves as a template, if the output type is
% different from the input type, e.g. for mapping arrays to cells and
% vice versa.
%
% This code is in the public domain.
mask = condition(in);
if nargin <= 4
out = in;
end
if sum(mask)
out(mask) = thenF(in(mask));
end
if sum(~mask)
out(~mask) = elseF(in(~mask));
end
end
Use it like this:
f = @(y)(iif(@(x)(x > 3), @(x)(x.^2), @(x)(x/2), y))
f(linspace(0,6,10))
Solution 4
There is no built-in solution for this, but you can write an IIF yourself.
function result=iif(cond, t, f)
%IIF - Conditional function that returns T or F, depending of condition COND
%
% Detailed
% Conditional matrix or scalar double function that returns a matrix
% of same size than COND, with T or F depending of COND boolean evaluation
% if T or/and F has the same dimensions than COND, it uses the corresponding
% element in the assignment
% if COND is scalar, returns T or F in according with COND evaluation,
% even if T or F is matrices like char array.
%
% Syntax
% Result = iif(COND, T, F)
% COND - Matrix or scalar condition
% T - expression if COND is true
% F - expression if COND is false
% Result - Matrix or scalar of same dimensions than COND, containing
% T if COND element is true or F if COND element is false.
%
if isscalar(cond)
if cond
result = t;
else
result = f;
end
else
result = (cond).*t + (~cond).*f;
end
end
Solution 5
Inspired by Jonas' answer the function below also works for mixed type input and chars, for which his function isn't stable.
function out = iif(cond, a, b)
%IIF implements a ternary operator
% Use cell output for either char or mixed type input
if ischar(a) || ischar(b) || ~strcmp(class(a), class(b))
out = cell(size(cond));
[out{cond}] = deal(a);
[out{~cond}] = deal(b);
else
% Use array output and logical indexing
out = repmat(b, size(cond));
out(cond) = a;
end
end
Edit: weeded out the extra conditional options in the cell branch, which were apparently remnants of a previous mistake, this is probably faster, and definitely cleaner.
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Lance Roberts
Control Systems Engineer. Most people want to stick their head in the sand and ignore problems, in an effort to avoid conflict. I refuse to be that passive person. Problems are there to be fixed, which means that first they have to identified. Denial is not just a river in Egypt.
Updated on October 08, 2020Comments
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Lance Roberts over 3 years
In VBA I can do the following:
A = B + IIF(C>0, C, 0)
so that if C>0 I get
A=B+C
and C<=0 I getA=B
Is there an operator or function that will let me do these conditionals inline in MATLAB code?
-
Tim Williams over 11 yearspossible duplicate of Matlab conditional assignment
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Lance Roberts over 11 years@Tim Williams, No, I'm looking for INLINE.
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Jonas over 11 yearsHave a look at this blog post that shows how to create an inline function for
iff
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Lance Roberts over 11 years@Jonas, that worked great if you want to write up an answer with the link and an excerpt of the basics I'll upvote and accept it.
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Jonas over 11 years@LanceRoberts: I have created the answer
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Sanjay Manohar over 10 yearsFor an extension of @Alex's answer, see stackoverflow.com/a/15870464/93910
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Jonas over 11 years@EitanT: Yes, this works indeed well when you can multiply (though you may want to use parentheses around
~cond
). However, the other answer already mentioned it, so I though I'd not repeat the other answer. -
masterxilo over 10 yearsThis is the best approximation to a C ?: which will not evaluate the branch that is not taken. Unfortunately the syntax is meh.
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Wauzl over 9 yearsYou could even use this do define
iif = @(c,t,f) c.*(t-f) + f
, so you can even do things vectorised. I think your answer is the best MATLAB-solution for simple uses. -
Ben Voigt almost 8 yearsVector version doesn't handle NaN properly
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Cris Luengo about 5 yearsThis does not answer the question. Please take the tour before contributing to this site. Thanks!
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Cris Luengo over 3 yearsThe first method works only in Octave, it is not legal MATLAB syntax.
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vitaminace33 over 3 yearsIt is. Here an official example: Content Indexing with Curly Braces, {}. mathworks.com/help/matlab/matlab_prog/…
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Cris Luengo over 3 yearsYou can do
tern = {F,T}; tern = tern{bool+1}
, but you can’t dotern = {F,T}{bool+1}
. -
vitaminace33 over 3 yearsI see, I stand corrected. I will edit the answer to incorporate this.