Is there a short-hand for nth root of x in Python?
Solution 1
nth root of x
is x^(1/n)
, so you can do 9**(1/2)
to find the 2nd root of 9, for example. In general, you can compute the nth root of x as:
x**(1/n)
Note: In Python 2, you had to do 1/float(n)
or 1.0/n
so that the result would be a float
rather than an int
. For more details, see Why does Python give the "wrong" answer for square root?
Solution 2
You may also use some logarithms:
Nth root of x
:
exp(log(x)/n)
For example:
>>> from math import exp, log
>>> x = 8
>>> n = 3
>>> exp(log(x)/n)
2.0
Solution 3
Also: x**(n**-1)
, which is the same but shorter than x**(1/float(n))
Solution 4
If you prefer to apply this operation functionally rather than with an infix operator (the **
symbol), you can pass the base and exponent as arguments to the pow
function:
In [23]: (9**(0.5)) == pow(9, 0.5)
Out[23]: True
I am also fond of finding new uses for this Infix hack in Python although it's more of a fun aside than a heavy-duty solution. But you could effectively make your own personal symbol for this by doing the following:
class Infix:
def __init__(self, function):
self.function = function
def __ror__(self, other):
return Infix(lambda x, self=self, other=other: self.function(other, x))
def __or__(self, other):
return self.function(other)
def __rlshift__(self, other):
return Infix(lambda x, self=self, other=other: self.function(other, x))
def __rshift__(self, other):
return self.function(other)
def __call__(self, value1, value2):
return self.function(value1, value2)
root_of = Infix(lambda x,y: y**(1.0/x))
print 2 |root_of| 9
3.0
Solution 5
There is. It's just **
=)
Any nth root is an exponentiation by 1/n
, so to get the square root of 9, you use 9**(1/2)
(or 9**0.5
) to get the cube root, you use 9 ** (1/3)
(which we can't write with a simpler fraction), and to get the nth root, 9 ** (1/n)
.
Also note that as of Python 3, adding periods to integers to make them a float is no longer necessary. Saying 1/3
works the way you would actually expect it to, giving 0.333...
as result, rather than zero. For legacy versions of Python, you'll have to remember to use that period (but also critically wonder why you're using a legacy version of a programming language)
whytheq
Current addictions: DAX / POWERSHELL Time served with: (T-)sql / MDX / VBA / SSRS Would like more time for the following: C# Python Maxim: if you build something idiot-proof, the world will build a better idiot
Updated on July 09, 2022Comments
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whytheq almost 2 years
In maths, if I wish to calculate 3 to the power of 2 then no symbol is required, but I write the 2 small:
3²
. In Python this operation seems to be represented by the**
syntax.>>> 3**2 9
If I want to go the other direction and calculate the 2nd root of 9 then in maths I need to use a symbol:
2√9 = 3
Is there a short-hand symbol in Python, similar to
**
that achieves this i.e.2<symbol>9
? Or do I need to use themath
module? -
Nacib Neme over 10 yearsPrints 1 on Python 2.x, because 1/2 returns 0.
-
Admin over 10 yearsHowever, it is not shorter than
x**(1./n)
and probably slightly less accurate (but then again, this whole way of computing nth roots is less than optimal). -
whytheq over 10 years@NacibNeme - fine in 3.2.2
-
PersianGulf over 10 yearsso use:
Python 2.7.5+ (default, Sep 17 2013, 17:31:54) [GCC 4.8.1] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> 16**(0.5) 4.0 >>>