Is there an actual 4-bit integer data type in C++11

Question

I require a 4 bit integer in a design for less memory use. In any version of c++ ,c++11 ,c++14 any can be used for the design.

Solution 1

There is no native 4bit datatype. But you could use an 8bit one to hold two 4bit values in the high/low nibble.

Solution 2

no, but you can use:

struct A {
   unsigned int value1 : 4;
   unsigned int value2 : 4;
};

Comments

[Aman Gupta]

But the struct also use memory space ,so how much the total space is used in this case.

[πάντα ῥεῖ]

@emlai That's unfortunately not true.

[krzaq]

It would be true if you used uint8_t or char instead (assuming 8-bit char)

[Aman Gupta]

nibble is also used only in the struct. Is there any direct way to use the 4 bit int

[Richard Critten]

Note that sizeof(char) always returns 1, so nothing can be smaller than a char - even is char is not 8 bits wide.

[πάντα ῥεῖ]

@AmanGupta " Is there any direct way to use the 4 bit int" No.