Is there any trivial way to 'delete by date' using ´rm'- in bash?
Solution 1
Some versions of find support the -delete option, making it even more efficient...
find . -maxdepth 1 -type f -ctime -12 -delete;
Check your find man page (this has worked on most recent releases of Ubuntu for me)
Solution 2
I would combine find and rm (without pipe)
find . ...bunch of find criterias to select certain files (e.g. by date) .... -exec rm \{\} \;
EDIT: with parameters for your example it would be
find . -maxdepth 1 -type f -ctime -12 -exec rm \{\} \;
CAVEAT: This works just today :-). (To make it work everytime, replace the -ctime with absoulte time, see timeXY in the manpage )
Solution 3
I would use:
find . -maxdepth 1 -type f -newerct 'jan 1' -print0 \
| xargs -0 rm
(or -newermt
if you want to filter on modification time)
Note that the 't' form of -newerXY will allegedtly allow any date format compatible with cvs (see doco).
Solution 4
Instead of parsing ls(1) which can too easily break you should rely on stat(1):
stat -c '%z/%n' files_or_glob | grep '^date' | cut -d/ -f2- | xargs -d '\n' rm -i
e.g.
$ stat -c '%z/%n' *| grep '^2008-12-16' | cut -d/ -f2- | xargs -d '\n' rm -i
Note: this will not handle filenames with embedded newlines correctly. However they are rarely found in the wil.d
Solution 5
find(1)
is a much more efficient to do what you want than parsing ls(1)
output.
EDIT: something to watch for is filenames with spaces in them so you want to have a find
which supports -print0
(to be used with xargs -0
) for better performance.
find . -mtime +12 -print0 | xargs -0 rm -f
Comments
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Fergie almost 2 years
I noticed today (after ~8 years of happily hacking away at bash) that there is no trivial way to 'delete by date' using ´rm'. The solution is therefore to pipe stuff around a combination of commands like rm, ls, find, awk and sed.
Say for example I wanted to delete every file in the working directory from 2009, what would be the typical approach?
I came up with the following, which is butt-ugly and should only be run if 'rm' is set to skip over directories (otherwise you will delete the parent directory):
ls -la | awk '{if (substr($6,0,5)==2009) print $8}' | xargs rm
Points for both the most elegant and the most outrageously over-engineered solutions.
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OIS over 15 yearsExample here: howtogeek.com/howto/ubuntu/…
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Rob Kennedy over 15 yearsIs there any danger of "rm" interpreting a file name as a command switch in this scenario, and thus deleting too little or too much?
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Joachim Sauer over 15 years@Rob: Partially: "-exec" calls rm with only one argument each time, so there's only the danger to delete too little. You could replace "rm \{\} \;" with "rm -- \{\} \;" to avoid that.
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Fergie over 15 yearsnice- I like that there are no pipes or -execs
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porges over 15 years
\{\}
is superfluous; just use{}
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Alastair almost 15 yearsNice, except that it doesn't use rm as required in the question. I'm not trolling: using rm is a valid requirement if, for example, you want to use -i for interactive delete...
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MikeW almost 7 yearsWhere "ctime" indicates that the file's 'Changed timestamp' (in days/24hr periods) was updated: ON/EXACTLY: no sign on number BEFORE/EARLIER: negative sign AFTER/LATER: positive + sign. Hence above example deletes files which were changed more than 12 days ago from now.
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MikeW almost 7 yearsNote: Busybox 'find' does not support ctime and several other related options.