Jackson Converting String to Object

33,080

Just putting the comment by @pvpkiran in an answer.

Use ObjectMapper class from com.fasterxml.jackson.databind

ObjectMapper objectMapper = new ObjectMapper();

Converting from Object to String:

String jsonString = objectMapper.writeValueAsString(link);

Converting from String to Object:

Link link = objectMapper.readValue(jsonString, type)
Share:
33,080
ytibrewala
Author by

ytibrewala

Updated on July 14, 2022

Comments

  • ytibrewala
    ytibrewala almost 2 years

    Link.java

    @JsonInclude(JsonInclude.Include.NON_NULL)
    @JsonPropertyOrder({ "rel", "href","method" })
    public class Link {
    
        @JsonProperty("rel")
        private String rel;
        @JsonProperty("href")
        private String href;
        @JsonProperty("method")
        private Method method;
    
        @Override
        public String toString() {
            return ToStringBuilder.reflectionToString(this);
        }
    }
    

    I have this third party class with fasterxml jackson annotations. I can convert a given object into a string using the specified toString() method. Is there any way of using that String to get an object of type Link?

    Note: The object itself has an embedded object (which has several more embedded objects) and these too needs to be converted into a Method object from the string itself.

  • Lova Chittumuri
    Lova Chittumuri almost 6 years
    we can also call like this String jsonString = objectMapper.writeValueAsString(Object);
  • aswzen
    aswzen over 2 years
    what if don't know what is the class type?