Jackson Converting String to Object
33,080
Just putting the comment by @pvpkiran in an answer.
Use ObjectMapper class from com.fasterxml.jackson.databind
ObjectMapper objectMapper = new ObjectMapper();
Converting from Object to String:
String jsonString = objectMapper.writeValueAsString(link);
Converting from String to Object:
Link link = objectMapper.readValue(jsonString, type)
Author by
ytibrewala
Updated on July 14, 2022Comments
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ytibrewala almost 2 years
Link.java
@JsonInclude(JsonInclude.Include.NON_NULL) @JsonPropertyOrder({ "rel", "href","method" }) public class Link { @JsonProperty("rel") private String rel; @JsonProperty("href") private String href; @JsonProperty("method") private Method method; @Override public String toString() { return ToStringBuilder.reflectionToString(this); } }
I have this third party class with fasterxml jackson annotations. I can convert a given object into a string using the specified toString() method. Is there any way of using that String to get an object of type Link?
Note: The object itself has an embedded object (which has several more embedded objects) and these too needs to be converted into a Method object from the string itself.
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Lova Chittumuri almost 6 yearswe can also call like this String jsonString = objectMapper.writeValueAsString(Object);
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aswzen over 2 yearswhat if don't know what is the class type?