Jackson deserialize JSON with timestamp field
28,158
I think you need to set the expected date/time format using @JsonFormat
annotation as shown below.
class MyObject {
private Boolean debug;
@JsonFormat(pattern="yyyy-MM-dd HH:mm:ss.SSS")
private Timestamp switchTime;
//...getters, setters, constructors
}
You can also set timezone as @JsonFormat(pattern="yyyy-MM-dd HH:mm:ss.SSS",timezone="PST")
Author by
Kiril Mytsykov
Updated on July 05, 2022Comments
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Kiril Mytsykov almost 2 years
I have such string:
{ "debug":"false", "switchTime":"2017-04-12 17:04:42.896026" }
I'm trying to get object in such approach:
new ObjectMapper().readValue(string, MyObject.class);
And MyObject class:
class MyObject { private Boolean debug; private Timestamp switchTime; //...getters, setters, constructors }
I have such exception:
com.fasterxml.jackson.databind.exc.InvalidFormatException: Can not deserialize value of type java.sql.Timestamp from String "2017-04-12 17:04:42.896026": not a valid representation (error: Failed to parse Date value '2017-04-12 17:04:42.896026': Can not parse date "2017-04-12 17:04:42.896026Z": while it seems to fit format 'yyyy-MM-dd'T'HH:mm:ss.SSS'Z'', parsing fails (leniency? null)) at [Source: {"debug":"false", "switchTime":"2017-04-12 17:04:42.896026"};
I don't understand why...If i use in debug mode Timestamp.valueOf() with "2017-04-12 17:04:42.896026" - i have success