Java Digits Validation

Question

I'm using validation in a int attribute:

@Digits(integer=6,fraction=0)
private Integer idOrder;

But I wanted this attribute has exactly 6 digits.

How can I do that? (Using JSP+Spring+Hibernate)

Solution 1

As you need the 6 digits, I think you should use a String to the property. If in some situations you need it as int, you make a

 public int getIdOrder(){ return Integer.parseInt(idOrder);}

On the String you can use pattern validation. It would be somethind like this:

@Pattern(regexp="\\d{6}")
private String idOrder;

Another option, is keep the idOrder a int and make a getter for the string:

public String getIdOrgetAsString(){
    String s = "000000" + idOrder;
    return s.substring(s.length() - 6);
}

Anyway, there are some options.

Solution 2

Are you sure your validation works at all?

The Hibernate documentation says:

Check whether the property is a number having up to integer digits and fraction fractional digits. 1

What means exactly 6 digits? Are leading zeros supported? Or should the number be between 100.000 and 999.999. In the first case, I guess your number should be a String (with @Length), and in the second case, I guess you should use @Min and @Max.

Comments

[Renato Shumi]

It is not working. Exactly 6 digits I mean 6 numbers, like: 000000, 020123, 123452,...

[Stefan Jansen]

In that case, using a String with @Length should work. If it does not, I guess your validation does not work at all. Or does a String not fit in your use case? And so, why not?

[Renato Shumi]

I must use int ou Integer. @Lenght just works with Strings.

[Brendan Long]

@RenatoShumi An int never has leading digits, so your code is already correct as far as I can tell.