Java do while loop increment
Solution 1
when you are doing a while loop as (i++ < 15) , it checks the condition and stop the loop if i++ is < 15 , But here when you do a do while loop j++ the loop goes 2 times and when it comes to while (i++ < 15) it increaments the value of i by 1 and stops... so in second loop the value of i increases by one but the function inside the while loop remains the same as it stops when i++ is > than 15
IF you do the following you will get 31
int i = 10;
int j = 0;
do {
j++;
System.out.println("loop:" + j);
while (i < 15) { //line6
i++
i = i + 20;
System.out.println(i);
} ;
} while (i < 2);
System.out.println("i_final:" + i);
Solution 2
While loop will be executed twice before its break.
while (i++ < 15) { //line6
i = i + 20;
System.out.println(i);
} ;
First it increment to 11 .
Check with 15. Returns true.
Now it increments to 31. (i = i + 20
)
now again while loop .
it increments the value .
Solution 3
First time when while loop condition is checked i=11, after that i is incremented by 20, so i=31. Then while condition is checked again, when found that 31 < 15 is false i is still incremented by 1. So i =32
user1144004
Updated on June 22, 2022Comments
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user1144004 almost 2 years
int i = 10; int j = 0; do { j++; System.out.println("loop:" + j); while (i++ < 15) { //line6 i = i + 20; System.out.println(i); } ; } while (i < 2); System.out.println("i_final:" + i);
Output:
loop:1 31 i_final:32
Why the
i_final
is32
and not31
? As we can see thedo_while
loop has executed only once, so line 8 should also have executed only once, hence incrementing the value of "i" by 1. When did31
increment to32
?