Java: How to make this Serializable?
22,874
Solution 1
Implementing Serializable
will do the trick, but you must write the object with an ObjectOutputStream, not just an OutputStream.
Solution 2
You just need to inherit from java.io.Serializable
:
public class XY implements Comparable<XY>, java.io.Serializable
Check more about serialization here.
Solution 3
Please see the SerializationUtils API provided by Apache Commons Lang.
This is much safer and more maintenance friendly. :)
Author by
Lucas Arrefelt
Updated on July 12, 2022Comments
-
Lucas Arrefelt almost 2 years
I need the following class to be Serializable.
package helpers; public class XY implements Comparable<XY> { public int x; public int y; public XY (int x, int y) { this.x = x; this.y = y; } public int compareTo( XY other ) { String compare1 = this.x + "-" + this.y; String compare2 = other.x + "-" + other.y; return compare1.compareTo( compare2 ); } public String toString() { return this.x + "-" + this.y; } }
As of now, I can't send it as an object with outputstream..I´ve tried to implement Serializable, but that didn't work.