Java: Split last digit from the rest of the INT
16,625
Solution 1
int x = 1343248724;
int firstpart = x/10;
int secondpart = x%10;
System.out.println(firstpart);
System.out.println(secondpart);
Mod (%) gives you the remainder which will be the last digit if you mod 10 Divide will drop the last digit. That way you don't have to actually search the string.
Doing all the length stuff seems a little like overkill to me
oh and to get your param as a int I would use
Interger.decode(fiscalId);
Solution 2
This is how you can get the Integers:
Integer firstPart = Integer.valueOf(
fiscalId.substring(0,fiscalId.length()-1));
Integer secondPart = Integer.valueOf(
fiscalId.substring(fiscalId.length()-1));
but I'd suggest getting ints instead:
int firstPart = Integer.parseInt(fiscalId.substring(0,fiscalId.length()-1));
int secondPart = Integer.parseInt(fiscalId.substring(fiscalId.length()-1));
Author by
BoDiE2003
Updated on June 14, 2022Comments
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BoDiE2003 almost 2 years
I have the next code, which gets a number, I need to split that number in to parts, firstPart should be the whole number without the last digit, and the secondPart should be only the last digit of the original number.
public Boolean verificationNumberFiscalId(String fiscalId) { // Trying to do a better wa yto do it Integer firstPart = fiscalId.length()-1; Integer secondPart = ??????????; // My old logic String NitValue = ""; for (Integer i = 0; i < fiscalId.length()-1; i++) { NitValue = fiscalId.substring(i,1); } Integer actualValueLength = fiscalId.length()-1; String digitoVerificador = fiscalId.substring(actualValueLength,1); return this.generateDigitoVerification(NitValue) == digitoVerificador; } /** * @param nit * @return digitoVerificador * @comment: Does the math logic */ public String generateDigitoVerification(String nit) { Integer[] nums = { 3, 7, 13, 17, 19, 23, 29, 37, 41, 43, 47, 53, 59, 67, 71 }; Integer sum = 0; String str = String.valueOf(nit); for (Integer i = str.length() - 1, j=0; i >= 0; i--, j++) { sum += Character.digit(str.charAt(i), 10) * nums[j]; } Integer dv = (sum % 11) > 1 ? (11 - (sum % 11)) : (sum % 11); return dv.toString(); }
Could you suggest me a better way to do it please? Thank you!