Javascript -- get only the variable part of a regex match
Solution 1
Javascript should return an array object on a regex match, where the zero index of the array is the whole string that was matched and the following indexes are the capture groups. In your case something like:
var myVar = regexp.exec(myString)[1];
should assign the value of the (.*?)
capture group to myVar
.
Solution 2
(Quotes from MDC)
Including parentheses in a regular expression pattern causes the corresponding submatch to be remembered. For example,
/a(b)c/
matches the characters'abc'
and remembers'b'
.
Since .*?
is the first (and only) remembered match, use $1
in your replacement string:
var foo = myString.replace(regexp, '$1');
Edit: As per your comment, you can also (perhaps with clearer intention) do this:
var foo = regexp.exec(myString)[1];
Related videos on Youtube
morgancodes
Programmer/artist working on a monster javascript project for a cable television company for the past two and a half years. Meanwhile, I build magical sound experiences for iOS including Thicket, Morton Subotnick's Pitch Painter, and this fun toy payed for by gum. I also like to make geometric sculptures from paper. Future plans include releasing my C++ audio patching engine (build on top of STK) as an open source project, creating the world's most mesmerizing musical video game, building my own programming language, and finding a way to pay for it all.
Updated on April 27, 2022Comments
-
morgancodes almost 2 years
given:
var regexp = new RegExp("<~~include(.*?)~~>", "g");
What's the easist way in javascript to assign a variable to whatever's matched by .*?
I can do this, but it's a little ugly:
myString.match(regexp).replace("<~~include", "").replace("~~>", "");
-
morgancodes over 13 yearsThanks bears. Thing is, I don't actually want to replace the whole thing, I just want to find out what the value of .*? is.
-
Matt Ball over 13 yearsNick just commented (and then deleted his comment) that the first version will also work. He's correct, but I guess the intention of the
replace
version is less clear than the intention of theexec
version. In either case, you have to assign the value returned byreplace
/exec
to another variable. -
Matt Ball over 13 yearsLookaround is not the answer. How is that supposed to help?
-
Skyler over 13 years[quote] Thanks bears. Thing is, I don't actually want to replace the whole thing, I just want to find out what the value of .*? is. – morgancodes 15 mins ago
-
Skyler over 13 yearsSo they could write a regex that Edit matches <~~include(.*?)~~> and excludes the information they do not want.
-
1.21 gigawatts over 7 yearsWon't this throw an error if there is no match? It returns null if there's no match so attempting to access the array index of a null object would throw an error.