Javascript: Passing a function with matches to replace( regex, func(arg) ) doesn't work

Question

According to this site the following replace method should work, though I am sceptical. http://www.bennadel.com/blog/55-Using-Methods-in-Javascript-Replace-Method.htm

My code is as follows:

text = text.replace( 
    new Regex(...),  
    match($1) //$.. any match argument passed to the userfunction 'match',
              //    which itself invokes a userfunction
);

I am using Chrome 14, and do not get passed any parameters passed to the function match?

Update:

It works when using

text.replace( /.../g, myfunc($1) );

The JavaScript interpreter expects a closure, - apparent userfunctions seem to lead to scope issues i.e. further userfunctions will not be invoked. Initially I wanted to avoid closures to prevent necessary memory consumption, but there are already safeguards.

To pass the arguments to your own function do it like this (wherein the argument[0] will contain the entire match:

result= text.replace(reg , function (){
        return wrapper(arguments[0]);
});

Additionally I had a problem in the string-escaping and thus the RegEx expression, as follows:

/\s......\s/g

is not the same as

new Regex ("\s......\s" , "g") or
new Regex ('\s......\s' , "g")

so be careful!

Solution

$1 must be inside the string:

"string".replace(/st(ring)/, "gold $1") 
// output -> "gold ring"

with a function:

"string".replace(/st(ring)/, function (match, capture) { 
    return "gold " + capture + "|" + match;
}); 
// output -> "gold ring|string"

Comments

[Lorenz Lo Sauer]

yes, in the string $1 is parsed by the replace function. In the code example $1 is just any variable, taken from the example in the link. --- It is best to pass arguments[0] though, because the last argument will contain the entire text.

[Twisty]

Took a bit to wrap my head around, but exactly what I needed.

[Abby Chau Yu Hoi]

modifiers are sufficient for his case.