Javascript string to Guid
24,705
Solution 1
I did it in string manipulation
var str = "798205486e954fa880a0b366e6725f71";
var parts = [];
parts.push(str.slice(0,8));
parts.push(str.slice(8,12));
parts.push(str.slice(12,16));
parts.push(str.slice(16,20));
parts.push(str.slice(20,32));
var GUID = parts.join('-');
console.log(GUID) // prints expected GUID
I did it this way because I don't like inserting characters between strings. If there is any problem tell me.
Or you could use a for
loop like bellow
var str = "798205486e954fa880a0b366e6725f71";
var lengths = [8,4,4,4,12];
var parts = [];
var range = 0;
for (var i = 0; i < lengths.length; i++) {
parts.push(str.slice(range,range+lengths[i]));
range += lengths[i];
};
var GUID = parts.join('-');
console.log(GUID);
Solution 2
Cleanest way?
Shortest:
var txt = shift.employee.id;
txt.replace(/([0-z]{8})([0-z]{4})([0-z]{4})([0-z]{4})([0-z]{12})/,"$1-$2-$3-$4-$5");
//"79820548-6e95-4fa8-80a0-b366e6725f71"
or if you don't care about the acceptable characters, it can be be even shorter (and cleaner):
txt.replace(/(.{8})(.{4})(.{4})(.{4})(.{12})/,"$1-$2-$3-$4-$5"); //boom!
Some don't like using regex for everything, but I liked it.
Solution 3
You could use an regular expression:
var rxGetGuidGroups = /(\w{8})(\w{4})(\w{4})(\w{4})(\w{12})/,
employeeId = shift.employee.id.replace(rxGetGuidGroups, '$1-$2-$3-$4-$5');
Solution 4
Try this function, It will return string in GUID format
function getGuid(str){
return str.slice(0,8)+"-"+str.slice(8,12)+"-"+str.slice(12,16)+
"-"+str.slice(16,20)+"-"+str.slice(20,str.length+1)
}
Author by
Linc Abela
Updated on November 10, 2020Comments
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Linc Abela over 3 years
in javascript, what is the easiest way to convert this string
798205486e954fa880a0b366e6725f71
to GUID format like this
79820548-6e95-4fa8-80a0-b366e6725f71
this is the messy way I do it :) im looking for the cleanest way
var employeeId = shift.employee.id.substring(0, 8) + "-" + shift.employee.id.substring(8, 12) + "-" + shift.employee.id.substring(12, 16) + "-" + shift.employee.id.substring(16, 20) + "-" + shift.employee.id.substring(20, 32);
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Linc Abela almost 10 yearsI am just looking if any that exist natively... i can do it with string manipulation.. but I was thinking if theres clean way
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Gunner over 7 yearsThe question is how to parse an existing guid. Not how to generate a new guid.
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NoRelect about 5 yearsThis solution does not always generate a valid
guid
as some bits of a guid have to be set to a specific value, see: en.wikipedia.org/wiki/Universally_unique_identifier#Format